Question

我有一个包含PHP代码的div（它从数据库打印数据）。我创建了一个AJAX函数来将数据发送到服务器而不刷新页面，这里是代码：

var url = "loadsave.php";

   $('.create_save').submit(function(event) {
        if ($('.gss_new_save').val()==""){
            event.preventDefault();     
        } else {
            $.ajax({
                    type: "POST",
                    url: url,
                    data: $('form').serialize(),
                    success: function()
                    {

                    }
                });
            event.preventDefault();
        }
    });

这是打印代码的另一部分。问题是它只是在刷新页面时打印代码：

<?php
            $connect = new PDO('mysql:host=localhost;dbname=game','root','');
            $cmd = $connect->query('SELECT * FROM saves');
            $result = $cmd -> fetchAll(PDO::FETCH_ASSOC);

            foreach ($result as $res) {
                ?>
                <div class="gss_save cls">
                    <span class="gss_save_text cls"><?php echo $res['name'];?></span>
                    <span class="gss_level">lvl: <?php echo $res['level'];?></span>
                </div>
                <?php
            }
        ?>

编辑：我补充说：表格：

<form method="post" action="loadsave.php" class="create_save">
            <input type="text" class="gss_new_save" name="name">
            <input type="submit" style="display:none">
        </form>

和loadsave.php的内容：

<?php
        if (isset($_POST['name'])) {
            $nombre = $_POST['name'];   
        }

        $connect = new PDO('mysql:host=localhost;dbname=game','root','');

        $stm = $connect->query("SELECT * FROM saves WHERE `name` ='$nombre'");
        $result = $stm->fetchAll(PDO::FETCH_ASSOC);

        if(count($result)==0){
            $cmd = $connect->prepare('INSERT INTO saves (name, level) VALUES (:nombre,"1")');
            $cmd -> bindParam(":nombre",$nombre);
            $cmd -> execute();
        }
    ?>

它就像一个魅力，但我想刷新div来打印我刚发送的内容，我怎样才能实现这个目标？

Answer 1

假设脚本回显了新内容：

success:function(response) {
    $("#divID").html(response);
}

loadsave.php应该是：

<?php
    if (isset($_POST['name'])) {
        $nombre = $_POST['name'];   
    }

    $connect = new PDO('mysql:host=localhost;dbname=game','root','');

    $stm = $connect->query("SELECT * FROM saves WHERE `name` ='$nombre'");
    $result = $stm->fetchAll(PDO::FETCH_ASSOC);

    if(count($result)==0){
        $cmd = $connect->prepare('INSERT INTO saves (name, level) VALUES (:nombre,"1")');
        $cmd -> bindParam(":nombre",$nombre);
        $cmd -> execute();
    }

    $cmd = $connect->query('SELECT * FROM saves');
    $result = $cmd -> fetchAll(PDO::FETCH_ASSOC);

    foreach ($result as $res) {
        ?>
        <div class="gss_save cls">
            <span class="gss_save_text cls"><?php echo $res['name'];?></span>
            <span class="gss_level">lvl: <?php echo $res['level'];?></span>
        </div>
        <?php
    }

?>

重新加载AJAX成功的div

1 个答案: