Question

我在WordPress网站上排序评分最高的帖子时遇到问题。

我想排序并显示评分最高的得分最高的帖子（rating_full）（rating_count）。

两者都是类型：LongString。

排序示例：

Business 4的评分为4.5 / 5 - 3票
Business 2的评分为4.5 / 5 - 1票
Business 1的评分是3.5 / 5 - 2票

在感兴趣的代码区域：

orderby评级是我在代码中关注的部分。

($orderby == 'rating')

代码中帖子的评分为＆quot; rating_full＆＃39; 。（比例为1到5）

代码中的帖子的投票数为＆＃39; rating_count＆＃39; （投票数）

两者都是类型：LongString

这是数据库结构和数据的图像： http://s22.postimg.org/wojlwqlz5/database.png

以下是我的代码。我注意到我的排序并不总是根据rating_full对帖子进行排序。我不确定为什么。我没有尝试实现计数DESC，因为我不确定。

// Sorting
add_filter('posts_join', 'directorySortingJoin',10,2);
function directorySortingJoin($join, $query) {
global $wpdb, $aThemeOptions;
    if ($query->is_main_query() && !$query->is_admin && ((isset($_GET['dir-    search'])) || (isset($query->query_vars["ait-dir-item-category"])) ||         (isset($query->query_vars["a-dir-item-location"])))) {
    $sql = "";
    // default ordering
    $orderby = (isset($aThemeOptions->directory->defaultOrderby)) ?  $aThemeOptions->directory->defaultOrderby : 'post_date';
    // get from get parameters
    if (!empty($_GET['orderby'])) {
        $orderby = $_GET['orderby'];
    }
    if ($orderby == 'rating') {
        $sql .= " LEFT JOIN {$wpdb->postmeta} rating ON ({$wpdb->posts}.ID  = rating.post_id AND rating.meta_key IN ('rating_full'))";
    }
    if ($orderby == 'packages') {
        directorySaveUserPackagesToDb();
        $sql .= " LEFT JOIN {$wpdb->usermeta} packages ON ({$wpdb- >posts}.post_author = packages.user_id AND packages.meta_key IN    ('dir_package'))";
    }
    if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
        $sql .= " LEFT JOIN {$wpdb->postmeta} featured ON ({$wpdb->posts}.ID = featured.post_id AND featured.meta_key IN ('dir_featured'))";
    }
    $join .= $sql;
    }
return $join;
    }
    add_filter('posts_orderby', 'directorySortingOrderby',10,2);
    function directorySortingOrderby($orderby, $query) {
global $wpdb, $aThemeOptions;
if ($query->is_main_query() && !$query->is_admin && ((isset($_GET['dir-  search'])) || (isset($query->query_vars["a-dir-item-category"])) ||     (isset($query->query_vars["a-dir-item-location"])))) {
    $sql = "";
    // default ordering
    $orderby = (isset($aThemeOptions->directory->defaultOrderby)) ?     $aThemeOptions->directory->defaultOrderby : 'post_date';
    $order = (isset($aThemeOptions->directory->defaultOrder)) ? $aThemeOptions->directory->defaultOrder : 'DESC';
    // get from get parameters
    if (!empty($_GET['orderby'])) {
        $orderby = $_GET['orderby'];
    }
    if (!empty($_GET['order'])) {
        $order = $_GET['order'];
    }
    if ($orderby == 'rating') {
        if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
            $sql = "featured.meta_value DESC, convert(rating.meta_value, decimal) {$order}";
        } else {
            $sql = "convert(rating.meta_value, decimal) {$order}";
        }
    } else if ($orderby == 'packages') {
        if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
            $sql = "featured.meta_value DESC, packages.meta_value   {$order}";
        } else {
            $sql = "packages.meta_value {$order}";
        }
    } else {
        if (isset($aThemeOptions->directory->showFeaturedItemsFirst)) {
            $sql = "featured.meta_value DESC, {$wpdb->posts}.{$orderby}   {$order}";
        }
    }
    $orderby = $sql;
       }
  return $orderby;
      }

Answer 1

我发现了这个问题！转换被用来代替演员。

$ sql =“convert（rating.meta_value，decimal）{$ order}”;

$ sql =“cast（rating.meta_value as decimal（10,2））{$ order}”;

如何在WordPress中按派生SQL列进行排序？

1 个答案: