我有一个XML文件,如下所示:
<report timestamp="3201" reportVersion="2" request="3981135340">
<question timedOut="false" time="3163" attempts="2" correct="true" id="13">
<answer status="attempt">
<radioButton correct="false" value="true" id="17" />
</answer>
<answer status="correct">
<radioButton correct="true" value="true" id="15" />
</answer>
</question>
</report>
我想根据'answer'节点的'status'属性读取子节点。
答案 0 :(得分:4)
使用XmlReader(最快但仅向前),XDocument(LINQ to XML)或XmlDocument。请参阅msdn文档中的示例。
答案 1 :(得分:1)
使用LINQ to XML:
using System.Xml.Linq;
var doc = XDocument.Parse(xml); // or XDocument.Load()
var elements = from e in doc.Descendants("answer")
where e.Attribute("status").Value == "attempt"
select e;
// elements will be IEnumerable<XElement>
答案 2 :(得分:0)
使用XmlDocument和XPath:
XmlDocument document = new XmlDocument();
//here you should load your xml for example with document.Load();
XmlNodeList nodes = document.SelectNodes("/report/question/answer[@status = 'correct']/radioButton");
只需根据需要修改XPath。
答案 3 :(得分:0)
尝试这个..
foreach (XmlNode xnode in xdoc.SelectNodes("report/question/answer"))
{
if (xnode.Attributes.GetNamedItem("status").Value == "correct")
{
string value = xdoc.SelectSingleNode("report/question/answer[@status='correct']/radioButton").Attributes.GetNamedItem("id").Value;
}
if (xnode.Attributes.GetNamedItem("status").Value == "attempt")
{
string value = xdoc.SelectSingleNode("report/question/answer[@status='attempt']/radioButton").Attributes.GetNamedItem("id").Value;
}
}