我确信这是一个简单的问题,但我找不到解决方案。我想保存发布到我的.NET Web服务的XML文件。我确信在调用服务时它只是一个简单的方法调用,但我找不到它。我想保存发布到服务的完整XML
非常感谢任何帮助。提前谢谢。
答案 0 :(得分:2)
感谢您的帮助,但我在http://msdn.microsoft.com/en-us/library/system.web.services.protocols.soapextension.aspx
找到了我想要的内容为了帮助其他新手来通过WebService实现这一点,我包括了我为实现它和修改而执行的步骤,因此我可以将它保存到db以及文件系统中,我执行了以下步骤。如果您有任何疑问,请随时联系我,我将很乐意回答。
创建了一些属性来存储值以保存到db
private string _requestXml;
private DateTime _start;
然后我修改了WriteInput方法,将值保存到那些变量中。
public void WriteInput(SoapMessage message)
{
//Begin Edit
oldStream.Position = 0;
_requestXml = new StreamReader(_oldStream).ReadToEnd();
_start = DateTime.UtcNow;
//End Edit
//Begin Original Code
oldStream.Position = 0;
Copy(oldStream, newStream);
var fs = new FileStream(filename, FileMode.Append, FileAccess.Write);
var w = new StreamWriter(fs);
var soapString = (message is SoapServerMessage) ? "SoapRequest" : "SoapResponse";
w.WriteLine("-----" + soapString + " at " + DateTime.Now);
w.Flush();
newStream.Position = 0;
Copy(newStream, fs);
w.Close();
newStream.Position = 0;
}
然后我将WriteOutput修改为
public void WriteOutput(SoapMessage message)
{
//Begin Edit
var responseXml = new StreamReader(newStream).ReadToEnd();
newStream.Position = 0;
//Start process for saving to DB
//"_requestXml" = Original Request Soap Message
//"responseXml" = Service Returned Response
//"_start" = Request Start Time
//message.MethodInfo.Name = I save this so I know what method from
//message.Url = I save this so I know the original ASMX that was hit
//End Edit
//Begin Original Code
newStream.Position = 0;
var fs = new FileStream(filename, FileMode.Append, FileAccess.Write);
var w = new StreamWriter(fs);
var soapString = (message is SoapServerMessage) ? "SoapResponse" : "SoapRequest";
w.WriteLine("-----" + soapString + " at " + DateTime.Now);
w.Flush();
Copy(newStream, fs);
w.Close();
newStream.Position = 0;
Copy(newStream, oldStream);
}
现在剩下的就是将以下内容添加到您的服务电话中,您应该好好去
[WebMethod, NameSpace.OfyourTraceExtesionClass.TraceExtension]
public void WebMethod1()
{
//DoSomeStuff
}
答案 1 :(得分:0)
如果要记录http post消息,解决它的一种优雅方法是在Web服务前设置一个简单的反向代理。在此代理中,您可以完全访问原始http请求。
答案 2 :(得分:0)
答案 3 :(得分:0)
[WebMethod]
public void XMLPersing()
{
var XMLDATA = "";
WriteLogCLS objWriteLog = new WriteLogCLS();
Stream receiveStream = HttpContext.Current.Request.InputStream;
receiveStream.Position = 0;
StreamReader readStream = new StreamReader(receiveStream, Encoding.UTF8); //For xml persing..
XMLDATA = readStream.ReadToEnd();
readStream.Close();
objWriteLog.WriteLog(Convert.ToString(XMLDATA));
XmlTextReader xmlreader = new XmlTextReader(Server.MapPath("Log/Exception/Sample.xml"));
DataSet ds = new DataSet();
ds.ReadXml(xmlreader);
xmlreader.Close();
if (ds.Tables.Count != 0)
{
var strCon = string.Empty;
strCon = ConfigurationManager.AppSettings["constring"];
SqlCommand cmdInsertXMLData = new SqlCommand();
SqlConnection SqlConn;
SqlConn = new SqlConnection(strCon);
try
{
cmdInsertXMLData = new SqlCommand("usp_InsertXML", SqlConn);
cmdInsertXMLData.CommandType = CommandType.StoredProcedure;
// cmdInsertLoginDetails.Parameters.Add("@XMLdata", SqlDbType.Xml).Value = ds.GetXml();
cmdInsertXMLData.Parameters.AddWithValue("@XMLdata", SqlDbType.Xml);
if (SqlConn.State == ConnectionState.Closed)
{
SqlConn.Open();
}
cmdInsertXMLData.ExecuteNonQuery();
// response = cmdInsertLoginDetails.Parameters["@Message"].Value.ToString();
}
catch (Exception ex)
{
objWriteLog.WriteLog("Error on XML Persing : " + ex.Message);
// response = "Error";
}
finally
{
if (cmdInsertXMLData != null)
{
cmdInsertXMLData.Dispose();
}
if (SqlConn.State == ConnectionState.Open)
{
SqlConn.Close();
SqlConn.Dispose();
}
objWriteLog = null;
}
// return response ;
}
}
}