编译一些属性的时间检查

时间:2015-04-06 10:11:42

标签: scala types

给出以下scala代码:

sealed trait Color
case object Red extends Color
case object Blue extends Color

sealed trait Car {
  def isBroken: Boolean
  def color: Color
}

如何定义这样的方法:

def fixBrokenRedCar(c: A): B

那就是AB应该是什么?该方法只应接受RedisBroken = true的汽车。否则它应该发出编译错误。此外,输出B应该包含有关其类型的信息,这样如果我创建另一个方法destroyRedCar(c: B)并将其应用于输出,它应该相应地编译。

2 个答案:

答案 0 :(得分:4)

您应该将数据移动到类型级别:

trait Bool
trait T extends Bool
trait F extends Bool

trait Color
trait Red extends Color
trait Blue extends Color

trait Car[Clr <: Color, Brkn <: Bool]

def fixBrokenCar[Cr <: Car[Red, T]](c: Cr) = new Car[Red, F]{}

scala> fixBrokenCar(new Car[Blue, T]{})
<console>:16: error: inferred type arguments [Car[Blue,T]] do not conform to method fixBrokenCar's type parameter bounds [Cr <: Car[Red,T]]
              fixBrokenCar(new Car[Blue, T]{})
              ^
<console>:16: error: type mismatch;
 found   : Car[Blue,T]
 required: Cr
              fixBrokenCar(new Car[Blue, T]{})
                           ^

scala> fixBrokenCar(new Car[Red, T]{})
res3: Car[Red,F] = $anon$1@67d9a642

To&#34; destroy&#34;它:

def destroyRedCar(c: Car[Red, _]) = true

scala> destroyRedCar(fixBrokenCar(new Car[Red, T]{}))
res10: Boolean = true

scala> destroyRedCar(new Car[Red, T]{})
res11: Boolean = true

scala> destroyRedCar(new Car[Blue, T]{})
<console>:15: error: type mismatch;
 found   : Car[Blue,T]
 required: Car[Red, ?]
              destroyRedCar(new Car[Blue, T]{})
                            ^

如果你需要&#34;变异&#34; Cr类型(从另一个类型构造一种类型,更确切地说):

trait Car[Clr <: Color, Brkn <: Bool] { 
   type Copy[C <: Color, B <: Bool] <: Car[C,B] // define "copy" type-method
}

trait BrandedCar[Clr <: Color, Brkn <: Bool] extends Car[Clr, Brkn] {
   type Copy[C <: Color, B <: Bool] = BrandedCar[C, B] // implement "copy" type-method
   def brand: String = "default"
}

def fixBrokenCar[Cr <: Car[Red, T]](c: Cr) = c.asInstanceOf[Cr#Copy[Red, F]]

def checkBrandedCar(c: BrandedCar[_, F]) = true // accepts only branded and fixed


scala> checkBrandedCar(new BrandedCar[Red, F]{})
res10: Boolean = true

scala> checkBrandedCar(new Car[Red, F]{})
<console>:15: error: type mismatch;
 found   : Car[Red,F]
 required: BrandedCar[?, F]
              checkBrandedCar(new Car[Red, F]{})
                              ^

scala> checkBrandedCar(fixBrokenCar(new BrandedCar[Red, T]{}))
res12: Boolean = true

您还可以在def copy[C <: Color, B <: Bool]: Copy[C, B]的特征中定义一些Car方法(例如案例类),而不仅仅是asInstanceOf

答案 1 :(得分:2)

我假设你可以改变你的班级结构。

实现您想要的一种方法是使用类型级编程。这里有一个非常好的堆栈溢出帖子:Scala type programming resources

以下是一些基于原始代码的示例代码,演示了如何使用Scala中的类型系统实现此目的。

/* 
 * Color traits I've left the same except converted the objects 
 * to classes. This would work just as well with traits. It might 
 * even be better if the Colors such as Red and Blue are traits
 * themselves that extend Color, I'm still just learning this 
 * method myself.
 */
sealed trait Color
class Red extends Color
class Blue extends Color

/* New trait to represent whether something is broken or not */
sealed trait IsBroken    
class Broken extends IsBroken
class NotBroken extends IsBroken

/* Change Car trait to have two type parameters, broken and color */   
trait Car[T <: Color, S <: IsBroken]

/* fixBrokenCar signature includes whether a car is broken and it's color */
def fixBrokenRedCar(c: Car[Red, Broken]): Car[Red, NotBroken]
    = new Car[Red, NotBroken]{}

val brokenRedCar = new Car[Red, Broken]{}
val fixedRedCar = new Car[Red, NotBroken]{}
val brokenBlueCar = new Car[Blue, Broken]{}

/* Compiles */
fixBrokenRedCar(brokenRedCar)

/* Doesn't compile */
fixBrokenRedCar(fixedRedCar)

/* Doesn't compile */
fixBrokenRedCar(brokenBlueCar)