Question

$（文件）。就绪（函数（）{ $（ '＃显示'）。点击（函数（）{ $就（{ 键入： “GET”，网址：“new1.php” 数据类型： “HTML”，异步：“假”，成功：功能（响应） { $（ “＃秀”）HTML（响应）。 } }）; }）; }）;

</head>

<input type="text" name="mono" method="post" class="tbox" >
<input type="button" name="submit" id="display" value="check">

<div id="show"> </div>

new1.php

<?php

    $username = "root";
    $password = "";
    $hostname = "localhost";


      $vah = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL");
 echo "Connected MySQL ";

  mysql_select_db("students",$vah);

 $pin =$_POST['mono'];
    //  $pin = isset($_POST['mono']) ? $_POST['mono']: '';


  $qry= "SELECT *FROM shop WHERE pin='$pin'";
  $res= mysql_query($qry);

  echo "<table border='1' >
        <tr>
        <td align=center> <b>pin</b></td>
        <td align=center><b>service</b></td>
        <td align=center><b>days</b></td>           
        </td> ";
        echo "</tr>";

        while($data = mysql_fetch_array($res))

        {   
            echo "<tr>";
            echo "<td align=center>$data[0]</td>";
            echo "<td align=center>$data[1]</td>";
            echo "<td align=center>$data[2]</td>";
            echo "</tr>";
        } 
        echo "</table>";
        ?>

Answer 1

我希望您在更新new.php之后解决错误，如下所示：

<?php

    $username = "root";
    $password = "";
    $hostname = "localhost";


      $vah = mysql_connect($hostname, $username, $password) or die("Unable to connect to MySQL");
 echo "Connected MySQL ";

  mysql_select_db("students",$vah);

 $pin =$_POST['mono'];
    //  $pin = isset($_POST['mono']) ? $_POST['mono']: '';


  $qry= "SELECT *FROM shop WHERE pin='$pin'";
  $res= mysql_query($qry);

  $html = "<table border='1' >
        <tr>
        <td align=center> <b>pin</b></td>
        <td align=center><b>service</b></td>
        <td align=center><b>days</b></td>           
        </td> ";
        echo "</tr>";

        while($data = mysql_fetch_array($res))

        {   
            $html += "<tr>";
            $html += "<td align=center>$data[0]</td>";
            $html += "<td align=center>$data[1]</td>";
            $html += "<td align=center>$data[2]</td>";
            $html += "</tr>";
        } 
        $html += "</table>";
        echo $html;
        ?>

使用php和ajax从数据库表中选择单个字段会将错误显示为未定义的索引

1 个答案: