逗号将矩阵与txt文件分开 - 续

时间:2015-04-06 08:20:08

标签: python matrix

我需要从包含表达式频率分布的文本文件列表中形成一个矩阵。因此,我从目录创建了所有文本文件(lof)的列表,并用它来构建矩阵(感谢gboffy)。该列表中的每个文件名的结构都是这样的:CompanyName-SerialNumber_IssueDate_IFRS.txt(例如:GoldmanSachs-123456_31.12.2014_IFRS.txt)。每个文件的内容结构也完全相同:

CompanyABC-123456_31.12.2012_IFRS.txt

Company ABC-123456_31.12.2012
financial statement:4
corporate-taxes:8
assets:2
available-for-sale property:0
auditors:213

Company123-789102_31.12.2012_IFRS.txt

Company123-789102_31.12.2012
financial statement:15
corporate-taxes:3
assets:8
available-for-sale property:2
auditors:23

我想要的输出应该是写入txt的单个矩阵文件,每个公司文件有一行,包括(CompanyName,Serial Number,IssueDate,Frequency1,Frequency2,...,FrequencyN):

'CompanyABC','123456','31.12.2012','4','8','2','0','213' \n
'Company123','789102','31.12.2012','15','3','8','2','23' \n

到目前为止,这是我的代码:

       def list_textfiles(directory, min_file_size):
            # Creates a list of all files stored in DIRECTORY ending on '.txt' with minimum file size
            textfiles = []
            for root, dirs, files in os.walk(directory):
                for name in files:
                    filename = os.path.join(root, name)
                    if os.stat(filename).st_size > min_file_size:
                        textfiles.append(filename)
            return textfiles

        directory = 'C:/CompanyFiles'
        minimum_size = 30000
        lof = list_textfiles(directory, minimum_size)

        res = []

        for f in lof:
            res += [[entry.split(':')[1] for entry in cdata ]
                    for cdata in [data.splitlines() for data in open(f).read().split('\n\n')]]

        with open('C:/CompanyFiles/Matrix.txt', 'wt') as outfile:
            outfile.write(str(res))

如何修改我的代码以实现上述输出?

2 个答案:

答案 0 :(得分:0)

这应该可以解决问题:

import os

outFile = 'C:/CompanyFiles/Matrix.txt'
folder = 'C:/CompanyFiles'

with open(outFile, 'w') as wfp:
    for f in os.listdir(inFolder):
        tmp = [line.rstrip() for line in open(os.path.join(folder, f), 'r')]
        arr = tmp[0].split('-')
        arr = [arr[0]] + arr[1].split('_')
        arr += [t.split(':')[1].strip() for t in tmp[1:]]
        wfp.write(','.join(["'" + e + "'" for e in arr]) + '\n')

注意:我没有彻底测试

答案 1 :(得分:0)

list of files

之后试试这个
#your code

lof = list_textfiles(directory, minimum_size)

for i in lof:
    with open(i) as f:
        for j in f:
            out_list = []
            split_to_out = j.split("-")
            out_list.append(split_to_out[0])
            out_list.append(split_to_out[1].split("_")[0])
            out_list.append(split_to_out[1].split("_")[1])
            temp = next(f, None)
            while temp:
                out_list.append(temp.split(":")[-1])
                temp = next(f, None)
            out_list = [i.strip() for i in out_list]
            to_write = ",".join(out_list) + "\n"
            with open('/home/quadloops/Matrix.txt', 'a') as outfile:
                outfile.write(str(to_write))

>>>cat Matrix.txt
Company ABC,123456,31.12.2012,4,8,2,0,213
Company123,789102,31.12.2012,15,3,8,2,23

更改为to_write = ",".join(out_list) + "\n"给出

>>>cat Matrix.txt
'Company ABC','123456','31.12.2012','4','8','2','0','213'   
'Company123','789102','31.12.2012','15','3','8','2','23'