我正在开发一个网络应用程序(PHP + MySQL),用户可以通过输入一些搜索字符串来搜索其他用户。
我需要将用户的输入字符串与我的数据库中“User”表的2列(username和fullName)相匹配,并返回最相关(20或50)的匹配。最理想的是,我还需要考虑拼写错误。
我该如何处理?我不打算在这里重新发明轮子。
答案 0 :(得分:1)
您可以使用MySQL full Text search执行此操作:
我想解释一下Boolean Full Text Search;但我建议你也请通过Full Text Search using Query Expansion。
让我们看看dev.mysql.com上给出的示例表:
mysql> select * from articles;
+----+-----------------------+------------------------------------------+
| id | title | body |
+----+-----------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 2 | How To Use MySQL Well | After you went through a ... |
| 3 | Optimizing MySQL | In this tutorial we will show ... |
| 4 | 1001 MySQL Tricks | 1. Never run mysqld as root. 2. ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
| 6 | MySQL Security | When configured properly, MySQL ... |
+----+-----------------------+------------------------------------------+
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('"database comparison"' IN BOOLEAN MODE);
+----+-------------------+------------------------------------------+
| id | title | body |
+----+-------------------+------------------------------------------+
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+-------------------+------------------------------------------+
当引用单词时,顺序很重要:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('"comparison database"' IN BOOLEAN MODE);
Empty set (0.01 sec)
当我们删除引号时,它会搜索包含“database”或“comparison”字样的行:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('database comparison' IN BOOLEAN MODE);
+----+---------------------+------------------------------------------+
| id | title | body |
+----+---------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+---------------------+------------------------------------------+
现在订单无关紧要:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('comparison database' IN BOOLEAN MODE);
+----+---------------------+------------------------------------------+
| id | title | body |
+----+---------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+---------------------+------------------------------------------+
如果我们想要获取包含单词“PostgreSQL”或短语“数据库比较”的行,我们应该使用此请求:
mysql> SELECT * FROM articles WHERE MATCH (title,body)
AGAINST ('PostgreSQL "database comparison"' IN BOOLEAN MODE);
+----+---------------------+------------------------------------------+
| id | title | body |
+----+---------------------+------------------------------------------+
| 1 | PostgreSQL Tutorial | DBMS stands for DataBase ... |
| 5 | MySQL vs. YourSQL | In the following database comparison ... |
+----+---------------------+------------------------------------------+
确保您搜索的字词不在list of stopwords中,但会被忽略。
(显然,像'是',''是stopwords这些词被忽略了)
要在布尔模式下增强结果排序,您可以使用以下查询:
(假设你在用户的输入字符串中总共有两个单词)那么。
SELECT column_names, MATCH (text) AGAINST ('word1 word2')
AS col1 FROM table1
WHERE MATCH (text) AGAINST ('+word1 +word2' in boolean mode)
order by col1 desc;
(如果用户的输入字符串中有3个单词)那么..
SELECT column_names, MATCH (text) AGAINST ('word1 word2 word3')
AS col1 FROM table1
WHERE MATCH (text) AGAINST ('+word1 +word2 +word3' in boolean mode)
order by col1 desc;
使用第一个 MATCH()
,我们会在非布尔搜索模式下获得分数(更有特色)。 第二 MATCH()
可确保我们确实只返回我们想要的结果(包含所有3个字)。
答案 1 :(得分:-1)
我会像搜索两列一样
我的查询就像这样
select * from(select * from user where(username like ='%{input}%'或lastName like'%{input}%'))和rownum = 20
您需要编写自定义清理算法来清除拼写错误输入