Question

我正在尝试按如下方式反序列化复杂的JSON对象：

public class StationaryOsbtacle
{
    public float latitude { get; set; }
    public float longitude { get; set; }
    public float cylinder_radius { get; set; }
    public float cylinder_height { get; set; }
}

public class MovingObstacle
{
    public float latitude { get; set; }
    public float longitude { get; set; }
    public float altitude_msl { get; set; }
    public float sphere_radius { get; set; }
}

public class RootObjectMovingObstacle
{
    public List<StationaryOsbtacle> stationary_osbtacles { get; set; }
    public List<MovingObstacle> moving_obstacles { get; set; }
}

JSON数据是：

{"stationary_osbtacles": [
    {
      "latitude": 33.833920,
      "longitude": -90.175781,
      "cylinder_radius": 20,
      "cylinder_height": 200
    }
  ],
  "moving_obstacles": [
    {
      "latitude": 33.833920,
      "longitude": -90.175781,
      "altitude_msl": 200,
      "sphere_radius": 20
    }
  ]}

如何单独反序列化每个属性（纬度，经度等）？

最后我尝试通过标签查看任何变量我正在使用以下代码并获取列表这段代码在计时器内，我不知道数组的大小是什么

        webRequest = (HttpWebRequest)WebRequest.Create("http://" + Ip.ToString() + ":" + Port.ToString() + "....."); // Create a request to get obstacles
        webRequest.Method = "GET";
        webRequest.KeepAlive = true;
        webRequest.ContentType = "application/x-www-form-urlencoded";
        webRequest.CookieContainer = cookieJar; //set container for HttpWebRequest 

        webResponse = (HttpWebResponse)webRequest.GetResponse(); // Get the response.

        using (var stream = webResponse.GetResponseStream())
        using (var reader = new StreamReader(stream))

        {
              var outObject = Newtonsoft.Json.JsonConvert.DeserializeObject<RootObjectMovingObstacle>(reader.ReadToEnd());
              my_label_latitude.Text = outObject.stationary_osbtacles.......?
        }

如何在此处显示标签上的任何实际变量？

Answer 1

使用Newtonsoft JSON引擎：

var yourClass = Newtonsoft.Json.JsonConvert
   .DeserializeObject<RootObjectMovingObstacle>(...);

SO和谷歌上有很多例子。

Answer 2

您可以使用Newtonsoft JSON库使用简单的dynamic对象将任何json字符串解析为对象：

JsonReader jsonReader = new JsonTextReader(new StringReader(strJson)) { DateParseHandling = DateParseHandling.None };
dynamic jsonObj = JObject.Load(jsonReader);

反序列化复杂的JSON对象

2 个答案: