Question

我已经实施了StickyListHeaders，但它并没有按照我的意愿行事。标题似乎没有正确分组。请参见下图，每个（折叠）标题的图片。

正如您所见，标题2和4是相同的。它们具有相同的ID，但未按预期分组。

example

以下是我的适配器代码。（为了便于阅读，删除了与视图相关的代码）

public class PartyMemberArrayAdapter extends ArrayAdapter<PartyMember> implements View.OnClickListener, StickyListHeadersAdapter {

    private ArrayList<PartyMember> members;

    public PartyMemberArrayAdapter(Context c, ArrayList<PartyMember> members) {
        super(c, R.layout.list_item_party_member, members);
        this.members = members;
    }

    @Override
    public View getHeaderView(int i, View view, ViewGroup viewGroup) {
        HeaderViewHolder holder;
        View row;
        if (view == null) {
            LayoutInflater inflater = LayoutInflater.from(getContext());
            holder = new HeaderViewHolder();
            row = inflater.inflate(R.layout.list_header_party_member, viewGroup, false);
            holder.party = (TextView) row.findViewById(R.id.tv_list_header_party);
            row.setTag(holder);
        } else {
            row = view;
            holder = (HeaderViewHolder) view.getTag();
        }

        holder.party.setText(PartyUtil.getFullPartyNameFromAbbr(members.get(i).getParty()));
        return row;
    }

    @Override
    public long getHeaderId(int i) {
        //There's 8 different parties, each with 8 names with unique length as I use for ID.
        return PartyUtil.getFullPartyNameFromAbbr(members.get(i).getParty()).length();
    }

    private class HeaderViewHolder{
        TextView party;
    }

    @Override
    public int getCount() {
        return members.size();
    }

    @Override
    public PartyMember getItem(int position) {
        return members.get(position);
    }

    @Override
    public long getItemId(int position) {
        return position;
    }
}

我在这里遗漏了什么吗？仅仅为标题返回一个唯一ID才能正确分组是不够的？

Answer 1

通过实现排序算法解决了这个问题，该算法根据它们“属于”哪个标题对基础数据集进行排序。

    Collections.sort(members, new Comparator<PartyMember>() {
        public int compare(PartyMember p1, PartyMember p2) {
            return p1.getParty().compareToIgnoreCase(p2.getParty());
        }
    });

StickyListHeader没有正确分组标题

1 个答案: