Question

我有一个Surfaceview和一个AdView，我画了这样的广告：

    g=new GameView(this );
    setContentView(R.layout.activity_game);
    RelativeLayout layout = (RelativeLayout)findViewById(R.id.vMain);
    layout.addView(g);
     mAdView = new AdView(this); 
    mAdView.setAdSize(AdSize.BANNER);
    mAdView.setAdUnitId(myId);
    AdRequest adRequest = new AdRequest.Builder()
        .addTestDevice(AdRequest.DEVICE_ID_EMULATOR)
        .build(); 
    if(mAdView.getAdSize() != null || mAdView.getAdUnitId() != null)
    mAdView.loadAd(adRequest); 
    ((RelativeLayout)findViewById(R.id.vMain)).addView(mAdView  );
    mAdView.bringToFront();
     mAdView.setVisibility(View.GONE);

在Surfaceview上，隐藏它。现在我想通过从surfaceview调用它来显示它，这可能吗？我尝试创建这个函数：

public void hide(){
    mAdView.setVisibility(View.GONE);

}
public void show(){
    mAdView.setVisibility(View.VISIBLE);

}

并从surfaceview调用它，但它给了我＆＃34;只有创建视图的原始线程才能触及它的视图。“例外。我该怎么办？

Answer 1

我不知道您从哪个线程调用这些方法，但必须从主线程调用所有UI更新。使用：

runOnUiThread(new Runnable() {
    @Override
    public void run() {
        // Update you UI here.
    }
});

例如：

public void hide(){
    runOnUiThread(new Runnable() {
        @Override
        public void run() {
            mAdView.setVisibility(View.GONE);
        }
    });
}

public void show(){
    runOnUiThread(new Runnable() {
        @Override
        public void run() {
            mAdView.setVisibility(View.VISIBLE);
        }
    });
}

隐藏和显示Adview

1 个答案: