为什么Google Gson.toJson会丢失数据

时间:2015-04-05 18:17:36

标签: java json generics arraylist gson

我有五个班级:

CommentPaperWoundPaperDocumentWoundDoc

Comment是文字持有人 Paper是空的抽象类 WoundPaper扩展Paper并存储字符串和Comments的数组列表 Document是抽象类,存储<? extends Paper>的ArrayList WoundDoc扩展了Document

您可以在下面看到这些课程:

评论类:

public class Comment {

    private final String text;

    public static class Builder {
        private final String text;

        public Builder(String text) {
            this.text = text;
        }

        public Comment build(){
            return new Comment(this);
        }

    }

    private Comment(Builder builder) {
        this.text = builder.text;
    }

    public String getText() {
        return text;
    }

}

论文课:

public abstract class Paper {

    protected Paper(ArrayList<Comment> commentList) {
    }

}

WoundPaper类:

public class WoundPaper extends Paper {

    private final String imageUri;
    private final ArrayList<Comment> commentList;

    public static class Builder {
        private final String imageUri;
        private final ArrayList<Comment> commentList;

        public Builder(String imageUri, ArrayList<Comment> commentList) {
            this.imageUri = imageUri;
            this.commentList = commentList;
        }

        public WoundPaper build() {
            return new WoundPaper(this);
        }

    }

    private WoundPaper(Builder builder) {
        super(builder.commentList);
        this.imageUri = builder.imageUri;
        this.commentList = builder.commentList;
    }

}

文档类:

public abstract class Document {
    private final ArrayList<? extends Paper> paperList;


    protected Document(ArrayList<? extends Paper> paperList) {
        this.paperList = paperList;
    }

}

WoundDoc类:

public class WoundDoc extends Document {

    public static class Builder {
        private final ArrayList<WoundPaper> paperList;

        public Builder(ArrayList<WoundPaper> paperList) {
            this.paperList = paperList;
        }

        public WoundDoc build() {
            return new WoundDoc(this);
        }

    }

    private WoundDoc(Builder builder) {
        super(builder.paperList);
    }

}

现在我必须创建一个WoundDoc的实例并将其转换为Gson的JSON字符串。这是一个示例代码:

        Comment comment = new Comment.Builder("comment").build();
        ArrayList<Comment> commentList = new ArrayList<Comment>();
        commentList.add(comment);
        commentList.add(comment);

        WoundPaper woundPaper = new WoundPaper.Builder("some Uri", commentList).build();
        ArrayList<WoundPaper> woundPaperList = new ArrayList<WoundPaper>();
        woundPaperList.add(woundPaper);
        woundPaperList.add(woundPaper);

        WoundDoc woundDoc = new WoundDoc.Builder(woundPaperList).build();

        System.out.println("woundDoc to JSON >> " + gson.toJson(woundDoc));

但输出很奇怪:

  

woundDoc到JSON&gt;&gt; {&#34; paperList&#34;:[{},{}]}

正如我之前显示的那样,WoundDoc存储了WoundPaper的列表以及每个WoundPaper存储comment s的列表。但是为什么输出中没有comment

1 个答案:

答案 0 :(得分:3)

当gson序列化WoundDoc所有它可以告诉的是,有两个类型为List的对象延伸PaperList<? extends Paper>);具体类型未知。由于Paper没有gson可以使用的字段,因此只能说该列表中有两个条目,但因为它们是没有字段的类型Paper,所以没有办法工作如何序列化这些对象。

解决这个问题的一种方法是将类型从您的实现传递给抽象类,这样当gson检查它们时,它可以看到它遇到的对象是哪个类的实例,因此可以找出如何序列化它们。

更新文档以获取类型参数:

public abstract class Document<T extends Paper> {
    private final ArrayList<T> paperList;


    protected Document(ArrayList<T> paperList) {
        this.paperList = paperList;
    }
}

更新WoundDoc以将类型传递给Document:

public class WoundDoc extends Document<WoundPaper> {

如果您无法进行上述更改,另一种解决方法是为WoundDoc编写自定义序列化程序

我个人使用第一个解决方案和传递类型,因为我懒惰并且编写自定义序列化器更省力

编辑:轻微喊出jackson,如果您尝试序列化某些内容并且无法解决问题,则会引发异常。