jquery datatables - 按列名获取td

时间:2015-04-05 16:39:46

标签: jquery datatables

我想在特定行的td中添加一个类。我不想对数字索引大惊小怪,而是通过其列的名称访问td。换句话说,我想做这样的事情:

for each row in the table where the column "role" contains "some text" 
do add the "red" class to the td in the "email" column.

我找到了办法,但我对此并不满意;我发现它太复杂了。有人有更简单的建议吗?

在下面的示例中,我添加了类" red"列中的td"电子邮件"对于每一行都有一些文字"在"角色"柱:

tab = $("#myTable").dataTable({
    "data": dataset,
    "columns": [
            { "data": "uid", name: "uid" },
            { "data": "name", name: "name"},
            { "data": "role", name: "role"},
            { "data": "email", name: "email"}
    ]               
});

function GetTdByName(row, column_name) {
        var idx = row.nodes().column(column_name + ":name")[0]; 
        var selector = "td:eq(" + idx + ")";
        return row.nodes().to$().find(selector)
}

$("#btn").click(function() {
    var ta = $('#myTable').DataTable();
    ta.rows().every(function () {
            if ($.inArray(this.data().role , ["some text", "some other text,"] ) > -1) {    
                GetTdByName(this, "email").addClass("red");
            }
    })
})              

更新

我找到了一种更简洁的方法。实际上,大多数此解决方案都可以在官方文档中找到:column-selector

    ta.rows().every(function () {
        if ($.inArray(this.data().role , ["some text", "some other text,"] ) > -1) {    
            $(ta.column("email:name").nodes()[this.index()]).addClass("red");
        }
    })

1 个答案:

答案 0 :(得分:1)

有一个内置的回调:fnRowCallback。它可能不是您想要的代码,您使用按钮单击来应用该类,但这是您使用fnRowCallback将该类应用于表格渲染的方式:

tab = $("#myTable").dataTable({
    "data": dataset,
    "columns": [
            { "data": "uid", name: "uid" },
            { "data": "name", name: "name"},
            { "data": "role", name: "role"},
            { "data": "email", name: "email"}
    ],
   "fnRowCallback": function (nRow, aData, iDisplayIndex, iDisplayIndexFull) {
      if(aData[2] == 'some text'){
         $('td:eq(3)', nRow).addClass('red');
      }
   },
...