Question

好的，所以我有一个提取员工信息的SQL查询;职位，性别，工资率等。我有临时表，目前正在显示平均工资率。大。

现在我需要引入职称并保持平均工资率，但只限制男性和女性都在职位中的结果。帮助

非常感谢所有帮助！

另外，无论如何都要创建一个新列，显示男性和女性之间的薪酬差异吗？

If EXISTS (Select * FROM TempDB..SYSOBJECTS WHERE name =  '##JTemp')
BEGIN
    DROP TABLE ##JTemp
END
GO

SELECT
    e.EmployeeID AS 'Employee ID',
    c.FirstName + ' ' + c.LastName AS 'Employee Name',
    e.Gender AS 'Employee Gender',
    e.Title AS 'Job Title',
    edh.DepartmentID,
    d.Name AS 'Department Name',
    MAX(eph.Rate) AS 'Pay Rate',
    eph.PayFrequency AS 'Pay Frequency',
    MAX(eph.Rate) * eph.PayFrequency AS 'Rate x Frequency'
INTO
    ##JTemp
FROM
    HumanResources.Employee e
INNER JOIN 
    Person.Contact c on c.ContactID = e.EmployeeID
INNER JOIN 
    HumanResources.EmployeeDepartmentHistory edh on            
edh.EmployeeID = e.EmployeeID
INNER JOIN 
    HumanResources.Department d on d.DepartmentID = edh.DepartmentID
INNER JOIN 
    HumanResources.EmployeePayHistory eph on eph.EmployeeID = e.EmployeeID
WHERE
    edh.EndDate IS NULL
GROUP BY 
    e.EmployeeID, c.FirstName, c.LastName,
    e.Gender, e.Title, edh.DepartmentID,
    d.Name, eph.PayFrequency

SELECT
    [Job Title],
    [Employee Gender],
    AVG([Pay Rate]) AS 'Average Pay Rate',
    AVG([Rate x Frequency]) AS 'Average Rate x Frequency'
FROM
    ##JTemp
GROUP BY 
    [Job Title], [Employee Gender]
ORDER BY 
    [Job Title]

--WHERE [Employee Gender] = 'M'

IF EXISTS (Select * FROM TEMPDB..SYSOBJECTS WHERE name = '##JTemp')
BEGIN
    DROP TABLE ##JTemp
END
GO

Answer 1

Select
    j1.[Job Title],
    AVG(j1.[Pay Rate]) AS 'Average Pay Rate',
    AVG(j1.[Pay Frequency]) AS 'Average Rate x Frequency',
    (
        (Select AVG(j2.[Pay Rate])
        From ##JTemp j2
        Where j2.[Employee Gender] = 'M' 
            and j2.[Job Title] = J1.[Job Title]
        Group By
            j2.[Job Title])
        -
        (Select AVG(j2.[Pay Rate])
        From ##JTemp j2
        Where j2.[Employee Gender] = 'F' 
            and j2.[Job Title] = J1.[Job Title]
        Group By
            j2.[Job Title])
    ) as [Pay Rate Diff]
From 
    ##JTemp j1

Group By
    j1.[Job Title]
HAVING COUNT(DISTINCT j1.[Employee Gender]) = 2
Order By
    j1.[Job Title]

Answer 2

select m.[Job Title], m.ap, m.mp, f.ap, f.mp
 from (  Select [Job Title], AVG([Pay Rate]) as ap, max([Pay Rate]) as mp
           From ##JTemp
          Where [Employee Gender] = 'M' 
          Group By [Job Title] ) m
 join (  Select [Job Title], AVG([Pay Rate]) as ap, max([Pay Rate]) as mp
           From ##JTemp
          Where [Employee Gender] = 'F' 
          Group By [Job Title] ) f 
   on m.[Job Title] = f.[Job Title]

SQL - 如果只有当两个性别出现在同一个职称时才返回记录？

2 个答案: