Question

我尝试的代码：

import java.io.*;
import java.util.regex.*;
public class All {
    public static void main(String[] args) {
        String input = "IT&&faculty.*";
        try {
            FileInputStream fstream = new FileInputStream("uu.txt");
            DataInputStream in = new DataInputStream(fstream);
            BufferedReader br = new BufferedReader(new InputStreamReader(in));
            String strLine;
            while ((strLine = br.readLine()) != null) {
                if (Pattern.matches(input, strLine)) {
                    Pattern p = Pattern.compile("'(.*?)'");
                    Matcher m = p.matcher(strLine);
                    while (m.find()) {
                        String b = m.group(1);
                        String c = b.toString() + ".*";
                        System.out.println(b);

                        if (Pattern.matches(c, strLine)) {
                            Pattern pat = Pattern.compile("<(.*?)>");
                            Matcher mat = pat.matcher(strLine);
                            while (mat.find()) {
                                System.out.println(m.group(1));

                            }
                        } else {
                            System.out.println("Not found");
                        }
                    }
                }
            }
        } catch (Exception e) {
            System.err.println("Error: " + e.getMessage());
        }
    }
}

我的文本文件的内容是： \表示它是换行符

输入文件：

IT&&faculty('Mousum handique'|'Abhijit biswas'|'Arnab paul'|'Bhagaban swain')
 Mousum handique(designation|address|phone number|'IT Assistant          professor'|<AUS staff quaters>|#5566778899#)
 Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#)
Arnab paul(designation|address|phone number|'IT Assistant professor'|<AUE staff quaters>|#5566778890#)
Bhagaban swain(designation|address|phone number|'IT Assistant professor'|<AUW staff quarters>|#5566778892#)

它给出了结果 -

Mousum handique
Not found
Abhijit Biswas
Not found 
Arnab Paul
Not found
Bhagaban swain
Not found

而我想要的结果是：

Mousum handique
AUS staff quaters
Abhijit Biswas
AUW staff quaters
Arnab Paul
AUE staff quaters
Bhagaban swain
AUW staff quaters

我希望在第一场比赛之后，当它从文件中获得Mousum handique时，它应该再次搜索文件并且它在哪里得到像Mousum handique那样的线，它应该打印在＆lt;＆gt;内的任何内容对于那条相应的线。请参考我的文本文件的数据以了解我的问题。对不起，如果我的问题看起来很愚蠢，但我试了很多！

Answer 1

您不需要使用string.matches方法只需使用Patttern和Matcher类来提取该行开头的名称以及<>之间的内容在同一条线上。

String s =  "IT&&faculty('Mousum handique'|'Abhijit biswas'|'Arnab paul'|'Bhagaban swain')\n" + 
        " Mousum handique(designation|address|phone number|'IT Assistant           professor'|<AUS staff quaters>|#5566778899#)\n" + 
        " Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#)\n" + 
        "Arnab paul(designation|address|phone number|'IT Assistant professor'|<AUE staff quaters>|#5566778890#)\n" + 
        "Bhagaban swain(designation|address|phone number|'IT Assistant professor'|<AUW staff quarters>|#5566778892#)";
Matcher m = Pattern.compile("(?m)^\\s*([^\\(]+)\\([^\\)]*\\|<([^>]*)>[^\\)]*\\)").matcher(s);
while(m.find())
{
    System.out.println(m.group(1));
    System.out.println(m.group(2));
}

<强>输出：

Mousum handique
AUS staff quaters
Abhijit biswas
AUW staff quaters
Arnab paul
AUE staff quaters
Bhagaban swain
AUW staff quarters

DEMO

<强>更新

使用此正则表达式获取ID号。

String s =  "IT&&faculty('Mousum handique'|'Abhijit biswas'|'Arnab 
paul'|'Bhagaban swain')\n" + 
                " Mousum handique(designation|address|phone number|'IT Assistant           professor'|<AUS staff quaters>|#5566778899#)\n" + 
                " Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#)\n" + 
                "Arnab paul(designation|address|phone number|'IT Assistant professor'|<AUE staff quaters>|#5566778890#)\n" + 
                "Bhagaban swain(designation|address|phone number|'IT Assistant professor'|<AUW staff quarters>|#5566778892#)";
        Matcher m = Pattern.compile("(?m)^\\s*([^\\(]+)\\([^\\)]*\\|<([^>]*)>[^\\)]*\\|#([^#]*)#[^\\)]*\\)").matcher(s);
        while(m.find())
        {
            System.out.println(m.group(1));
            System.out.println(m.group(2));
            System.out.println(m.group(3));
        }

<强>输出：

Mousum handique
AUS staff quaters
5566778899
Abhijit biswas
AUW staff quaters
5566778891
Arnab paul
AUE staff quaters
5566778890
Bhagaban swain
AUW staff quarters
5566778892

Answer 2

这里有一个错误：

while (mat.find()) {
    System.out.println(m.group(1)); // <-- you should use mat - not m!!!
}

第二个错误在这里：

if (Pattern.matches(c, strLine)) {

由于字符串if是上一个匹配+“c”，因此永远不会输入此.*。删除这个if条件并且它将起作用。

固定代码：

    ...
    Pattern p = Pattern.compile("'(.*?)'");
    Matcher m = p.matcher(strLine);
    while (m.find()) {
        String b = m.group(1);
        System.out.println(b);            
        Pattern pat = Pattern.compile("<(.*?)>");
        Matcher mat = pat.matcher(strLine);
        while (mat.find()) {
            System.out.println(mat.group(1));

        }            
    }
    ...

使用输入

运行此代码

"Abhijit biswas(designation|address|phone number|'IT Assistant professor'|<AUW staff quaters>|#5566778891#)

输出：

IT Assistant professor
AUW staff quaters

使用java正则表达式读取文本文件以匹配多个模式

2 个答案: