我正在尝试制作一个雷达图,如附加image使用和ggplot2(或R中的任何其他包)。This谈论这个,但我的情况不同,因为我试图创建具有特定范围的响应数据的蜘蛛图。 我使用如下代码制作了一个情节,但我无法弄清楚如何在图像中制作它。请帮助我。
Impcts <- c("system","supply","security","well-being")
present <- c(5,5,3,5)
past <- c(6,6,4,5)
group.names <- c("present", "past")
ddf.pre <- data.frame(matrix(c(rep(group.names[1], 4), Impcts), nrow = 4, ncol = 2), var.order = seq(1:4), value = present)
ddf.pas <- data.frame(matrix(c(rep(group.names[2], 4), Impcts), nrow = 4, ncol = 2), var.order = seq(1:4), value = past)
ddf <- rbind(ddf.pre, ddf.pas)
colnames(ddf) <- c("Group", "Impcts", "var.order", "var.value")
library(ggplot2)
ggplot(ddf, aes(y = var.value, x = reorder(Impcts, var.order),
group = Group, colour = Group))+
coord_polar() +
geom_path() +
geom_point()+
labs(title = "Impacts Analysis").
答案 0 :(得分:4)
这是我的尝试。首先,我使用geom_path()
绘制了正方形。然后,我使用geom_polygon()
在方块顶部绘制了两个多边形。最后我添加了注释。
### Draw squares
mydf <- data.frame(id = rep(1:6, each = 5),
x = c(0, 6, 0, -6, 0,
0, 5, 0, -5, 0,
0, 4, 0, -4, 0,
0, 3, 0, -3, 0,
0, 2, 0, -2, 0,
0, 1, 0, -1, 0),
y = c(6, 0, -6, 0, 6,
5, 0, -5, 0, 5,
4, 0, -4, 0, 4,
3, 0, -3, 0, 3,
2, 0, -2, 0, 2,
1, 0, -1, 0, 1))
g <- ggplot(data = mydf, aes(x = x, y = y, group = factor(id)) +
geom_path()
### Draw polygons
mydf2 <- data.frame(id = rep(7:8, each = 5),
x = c(0, 6, 0, -5, 0,
0, 5, 0, -5, 0),
y = c(6, 0, -4, 0, 6,
5, 0, -3, 0, 5))
gg <- g +
geom_polygon(data = mydf2, aes(x = x, y = y, group = factor(id), fill = factor(id))) +
scale_fill_manual(name = "Time", values = c("darkolivegreen4", "brown4"),
labels = c("Past", "Present"))
### Add annotation
mydf3 <- data.frame(x = c(0, 6.5, 0, -6.5),
y = c(6.5, 0, -6.5, 0),
label = c("system", "supply", "security", "well-being"))
ggg <- gg +
annotate("text", x = mydf3$x, y = mydf3$y, label = mydf3$label, size = 3)
ggsave(ggg, file = "name.png", width = 10, height = 9)