Question

所以我创建了一个有3个单选按钮的表。我无法理解如何让每个单选按钮执行其命名任务[功能]。这是我的桌子的照片：

有人可以解释或给我一个关于如何为这些单选按钮提供功能的示例。因此，当编辑文本并选择“更新”并单击提交按钮时，它将更新数据库。

以下是此部分的代码：

<!DOCTYPE html PUBLIC>
<?php

$connection = mysql_connect('localhost', 'root', 'root');

//Test Connection
if (!$connection)
{
die ("Could not connct to the database: <br />". mysql_error());
}
//select db
mysql_select_db('Assets');


$sql1= "SELECT gid, gstmnt  FROM Goals";
$records1 = mysql_query($sql1);

//Adding functions to submit

//$gstmnt_up = $_POST['gstmnt'];
?>

<html>
<head>
<title>List of GOALS/List of SERVICES</title>
</head>

<body>

<table width='800' border='3' cellpadding='2' cellspacing='2'>
<tr>
    <h1>List of Goals</h1>
    <th>GID</th>
    <th width= '200'>Goal Statement</th>
    <!--Sumbit column-->
    <th  width= '85'>
        <form id="EditGoalForm" action="EditGoals.php" method="POST">
            <input type="submit" name="submit" value="Submit"/>
        </form>
    </th>

</tr>

<!--This is a paragraph. It is editable. Try to change this text.</p>-->


<?php
while ($gtable = mysql_fetch_assoc($records1)) {

    echo "<tr>";

    echo "<td>".$gtable['gid']."</td>";

    echo "<td><div id=textarea contenteditable>".$gtable['gstmnt']."</div></td>";

    echo "<td>
              <input type='radio' name=".$gtable['gid']."                                    value='asis' checked> AS-IS </br>
              <input type='radio' name=".$gtable['gid']." id='radio_update".$gtable['gid']." value='update' > Update     </br>
              <input type='radio' name=".$gtable['gid']."                                    value='delete' > Delete
          </td>";

    echo "</tr>";
    }

    echo "<td> </td>";

    echo "<td> 
              <input type= 'text name='addGoal' placeholder='ADD NEW GOAL HERE' size='100'>
          </td>";

    echo "<td> 
              <input type='checkbox' name='add' value='checked'> Add Goal
          </td>";
    ?>

    </table>

具有原样/更新/删除功能的单选按钮

0 个答案: