Question

目前正在阅读Head First Servlet Jsp。我目前停留在映射servlet。这可能是一个愚蠢的问题，但我如何正确映射servlet url模式？我正在使用eclipse火星，这是我第一次使用jsp / servlets。我总是在创建动态Web项目时检查生成web xml

这是默认的web.xml

<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://xmlns.jcp.org/xml/ns/javaee"
    xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_3_1.xsd"
    id="WebApp_ID" version="3.1">
    <display-name>HeadFirst</display-name>
    <welcome-file-list>
        <welcome-file>index.html</welcome-file>
        <welcome-file>index.htm</welcome-file>
        <welcome-file>index.jsp</welcome-file>
        <welcome-file>default.html</welcome-file>
        <welcome-file>default.htm</welcome-file>
        <welcome-file>default.jsp</welcome-file>
    </welcome-file-list>
</web-app>

使用此

运行

http://localhost:8080/HeadFirst/Ch2Servlet

但是当我在显示名称

下面添加它时

<servlet>
    <servlet-name>Ch2Servlet</servlet-name>
    <servlet-class>com.test.hello</servlet-class>
</servlet>
<servlet-mapping>
    <servlet-name>Ch2Servlet</servlet-name>
    <url-pattern>/HelloWorld</url-pattern>
</servlet-mapping>

它给我一个404错误，这是网址

http://localhost:8080/HeadFirst/servlet/com.test.hello.Ch2Servlet

这是我的servlet类

@WebServlet("/Ch2Servlet")
public class Ch2Servlet extends HttpServlet {
    private static final long serialVersionUID = 1L;
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
        PrintWriter out = response.getWriter();
        java.util.Date today = new java.util.Date();
        out.println("<h1>Hello World</h1>" + "<br>");
        out.println("Date today is " + today + "<br>");
    }
    protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    }
}

顺便说一下，我读过这篇文章，但仍感到困惑 Java Servlet URL Mapping Servlet Mapping using web.xml 编辑添加了我的serlvet类

Answer 1

网址不是：

http://localhost:8080/HeadFirst/servlet/com.test.hello.Ch2Servlet

它将是：

http://localhost:8080/HeadFirst/HelloWorld

更具体地说，它将是您设置为<url-pattern>...</url-pattern>

的值

如何映射servlet java

1 个答案: