所以我需要实现一个AJAX信息提交表单。我正在使用树屋里的人建造的这个例子...... http://blog.teamtreehouse.com/create-ajax-contact-form
问题的第一部分......如何添加新字段?我已经尝试编辑.php .js和.html,让它们全部符合我认为是正确的但是在测试时我的解决方案失败了。
我需要的字段...... 名称: 地点: 邮编: 出生日期: 网址链接: 消息(200字):
第二部分......我可以在同一页面上运行其中两个吗?
提前干杯以获得任何帮助! - 如果您希望我发送代码等,您可以给我发电子邮件garethyo@gmail.com
以下代码 -
<form id="ajax-contact" method="post" action="mailer.php">
<div class="field">
<label for="name">Name:</label>
<input type="text" id="name" name="name" required>
</div>
<div class="field">
<label for="email">Email:</label>
<input type="email" id="email" name="email" required>
</div>
<div class="field">
<label for="link">Link:</label>
<input type="text" id="link" name="link" required>
</div>
<div class="field">
<label for="message">Message:</label>
<textarea id="message" name="message" required></textarea>
</div>
<div class="field">
<button type="submit">Send</button>
</div>
</form>
JS
$(formMessages).text(response);
// Clear the form.
$('#name').val('');
$('#email').val('');
$('#link').val('');
$('#message').val('');
})
.fail(function(data) {
// Make sure that the formMessages div has the 'error' class.
$(formMessages).removeClass('success');
$(formMessages).addClass('error');
PHP
<?php
// My modifications to mailer script from:
// http://blog.teamtreehouse.com/create-ajax-contact-form
// Added input sanitizing to prevent injection
// Only process POST reqeusts.
if ($_SERVER["REQUEST_METHOD"] == "POST") {
// Get the form fields and remove whitespace.
$name = strip_tags(trim($_POST["name"]));
$name = str_replace(array("\r","\n"),array(" "," "),$name);
$email = filter_var(trim($_POST["email"]), FILTER_SANITIZE_EMAIL);
$message = trim($_POST["message"]);
// Check that data was sent to the mailer.
if ( empty($name) OR empty($message) OR !filter_var($email, FILTER_VALIDATE_EMAIL)) {
// Set a 400 (bad request) response code and exit.
http_response_code(400);
echo "Oops! There was a problem with your submission. Please complete the form and try again.";
exit;
}
// Set the recipient email address.
// FIXME: Update this to your desired email address.
$recipient = "garethyo@gmail.com";
// Set the email subject.
$subject = "A Future Bubbler… $name ";
// Build the email content.
$email_content = "Name: $name\n";
$email_content .= "Email: $email\n\n";
$email_content .= "Link: $link\n";
$email_content .= "Message:\n$message\n";
// Build the email headers.
$email_headers = "From: $name <$email>";
// Send the email.
if (mail($recipient, $subject, $email_content, $email_headers)) {
// Set a 200 (okay) response code.
http_response_code(200);
echo "Thank You! Your message has been sent.";
} else {
// Set a 500 (internal server error) response code.
http_response_code(500);
echo "Oops! Something went wrong and we couldn't send your message.";
}
} else {
// Not a POST request, set a 403 (forbidden) response code.
http_response_code(403);
echo "There was a problem with your submission, please try again.";
}
&GT;
答案 0 :(得分:0)
你永远不会定义$ link。你需要添加$ link = trim($ _ POST [&#39; link&#39;]);在$ message = trim之前($ _ POST [&#34; message&#34;]);. - 肖恩4月4日20:50
- 世界首席执行官肖恩