我有下表
batch_id time_start time_end day branch_id
1 4:30 PM 5:30 PM Monday 5
2 5:30 PM 6:30 PM Monday 4
1 4:00 PM 5:00 PM Tuesday 5
我的php中有以下表格代码
<table><tr><th><div><?php echo 'Batch Code';?></div></th>
<th><div><?php echo 'Mon';?></div></th>
<th><div><?php echo 'Tue';?></div></th>
<th><div><?php echo 'Wed';?></div></th>
<th><div><?php echo 'Thu';?></div></th>
<th><div><?php echo 'Fri';?></div></th>
<th><div><?php echo 'Sat';?></div></th>
<th><div><?php echo 'Sun';?></div></th>
</tr>
<tr>
<td>1</td><td>4:30 PM - 5:30 PM</td><td> </td><td> </td><td> </td><td> </td><td> </td><td> </td>
</tr>
<tr>
<td>2</td><td>5:30 PM - 6:30 PM</td><td> </td><td> </td><td> </td><td> </td><td> </td><td> </td>
</tr>
<tr>
<td>1</td><td> </td><td>4:00 PM - 5:00 PM </td><td> </td><td> </td><td> </td><td> </td><td> </td>
</tr>
</table>
我想要什么
我想要相同batch_id&amp;的时间相同的branch_id将在相应的日期显示
如上表所示,我有两个相同batch_id的记录,即 1 我希望星期一列中的数据将显示在星期一列中,星期二的数据将显示在星期二列中相同的batch_id&amp; same branch_id。
感谢您的帮助
更新 检查图像
答案 0 :(得分:1)
我假设您将结果集设置为以下数组。试试这个
<?php
$table = array(
0 => array(
'batch_id' => 1 ,
'time_start' => '4:30 PM',
'time_end' => '5:30 PM',
'day' => 'Monday'
),
1 => array(
'batch_id' => 2 ,
'time_start' => '5:30 PM',
'time_end' => '6:30 PM',
'day' => 'Monday'
),
2 => array(
'batch_id' => 1 ,
'time_start' => '4:00 PM',
'time_end' => '5:00 PM',
'day' => 'Tuesday'
)
);
//Arrange the array according to the batch number
$arrange_array = array();
foreach($table as $vals){
$arrange_array[$vals['batch_id']][] = $vals;
}
?>
<table>
<tr>
<th>
<div><?php echo 'Batch Code'; ?></div>
</th>
<th>
<div><?php echo 'Mon'; ?></div>
</th>
<th>
<div><?php echo 'Tue'; ?></div>
</th>
<th>
<div><?php echo 'Wed'; ?></div>
</th>
<th>
<div><?php echo 'Thu'; ?></div>
</th>
<th>
<div><?php echo 'Fri'; ?></div>
</th>
<th>
<div><?php echo 'Sat'; ?></div>
</th>
<th>
<div><?php echo 'Sun'; ?></div>
</th>
</tr>
<?php
foreach($arrange_array as $key => $days){
echo '<tr>
<td>'.$key.'</td>';
foreach($days as $batch){
echo '<td>'.$batch['time_start'].' - '.$batch['time_end'].'</td>';
}
echo '</tr>';
}
?>
</table>