Question

我在xamarin项目中使用TinyIoc，如果有必要，我可以更改IoC容器。我该如何解决这种情况？

internal class Program
{
    private static void Main(string[] args)
    {
        TinyIoC.TinyIoCContainer.Current.Register<IService, Service>();
        TinyIoC.TinyIoCContainer.Current.Register<ViewModel>();
        Model model; //From database... How I can inject this to my viewmodel?
        var viewModel = TinyIoC.TinyIoCContainer.Current.Resolve<ViewModel>();
    }
}

public class Model
{
    public object Data { get; set; }
}

internal interface IService
{
    string SomeMethod(Model model);
}

public class Service : IService
{
    public string SomeMethod(Model model)
    {
        //...
        return string.Empty;
    }
}

internal class ViewModel
{
    private readonly Model model;
    private readonly IService service;

    public string Name { get; private set; }

    public ViewModel(IService service, Model model)
    {
        this.model = model;
        this.service = service;
        this.Name = this.service.SomeMethod(this.model);
    }
}

我唯一想到的是：

internal class Program
{
    private static void Main(string[] args)
    {
        TinyIoC.TinyIoCContainer.Current.Register<IService, Service>();
        TinyIoC.TinyIoCContainer.Current.Register<ViewModel>();
        Model model; //From database... How I can inject this to my viewmodel?
        var viewModel = TinyIoC.TinyIoCContainer.Current.Resolve<ViewModel>();
        viewModel.Initialize(model);
    }
}

internal class ViewModel
{
    private Model model;
    private readonly IService service;

    public string Name { get; private set; }

    public ViewModel(IService service)
    {
        this.service = service;
    }

    public void Initialize(Model model)
    {
        this.model = model;
        this.Name = this.service.SomeMethod(this.model);
    }
}

但我真的不喜欢这样:-(我的设计不好？应该使用dependecy注射而不是construktor注射？或者另一个反对者可以这样做吗？

Answer 1

使用Func查看重载方法以查看哪一个最适合，因为我不知道TinyIoC如何处理注册实际实现。这样的事情可能有用：

.Register<ViewModel>(() => new ViewModel(
    TinyIoC.TinyIoCContainer.Current.Resolve<IService>(), 
    model));

或只是传递服务的新实例：

.Register<ViewModel>(() => new ViewModel(new Service(), model));

如果TinyIoC不适合该法案，那么您可以查看XLabs.IoC以寻找与Xamarin兼容的替代品：http://www.nuget.org/packages?q=xlabs.ioc

TinyIoC将模型注入到类构造函数中

1 个答案: