Question

我在这里举个例子： https://www.socketloop.com/tutorials/golang-create-new-xml-file

如果在工作人员之后更深入怎么办？

type Staff struct {
XMLName xml.Name `xml:"staff"`
ID int `xml:"id"`
FirstName string `xml:"firstname"`
LastName string `xml:"lastname"`
UserName string `xml:"username"`
Thing Thing `xml:"thing"`
}

我如何追加？我尝试过这样的事情：

v.Staffs = append(v.Staffs, Staff{ID: 108, FirstName: "Jennifer", LastName: "Loh", UserName: "jenniferloh", Thing.tape: "scotch"})

但是只有两个循环迭代的语句才能起作用并且难看：

v.Staffs = append(v.Staffs, Staff{ID: 108, FirstName: "Jennifer", LastName:    "Loh", UserName: "jenniferloh"})

v.Staffs.Thing[i] = append(v.Staffs.Thing, Thing{scotch: "tape"})

有更好的方法吗？感谢。

Answer 1

type Thing struct {
    stuff string `xml:"stuff"`
}

type Staff struct {
    XMLName xml.Name `xml:"staff"`
    ID int `xml:"id"`
    FirstName string `xml:"firstname"`
    LastName string `xml:"lastname"`
    UserName string `xml:"username"`
    Thing Thing `xml:"thing"`
}

stuff := Thing{Stuff: "120"}
v.Staffs = append(v.Staffs, Staff{ID: 108, FirstName: "Jennifer", LastName: "Loh", UserName: "jenniferloh", Thing: stuff})

Golang xml marshal附加项目更深？

1 个答案: