Question

好的，我有一个查询，需要在输出中显示所有周末日期，以及在星期日开始并在星期六结束的一周内审核callID的计数？

目前我正在插入startdate和enddate，但这不会累积输出中的周末。

我希望在输出中看到的是：

周末2/7/2015计数15（每位主管）
周末2/14/2015计数25
周末2/21/2015计数9

SELECT DISTINCT [Coach]。[LastName]＆amp; “，”＆amp; [Coach]。[FirstName] AS CoachName，Count（S.CallId）AS [Count]，tblLocations.LocationName，S.DateScored FROM tblLocations INNER JOIN（tblScores AS S INNER JOIN tblEmployees AS Coach ON S.CoachId = Coach.ID）ON tblLocations.ID = S.LocationId GROUP BY [教练]。[LastName]＆amp; “，”＆amp; [Coach]。[FirstName]，tblLocations.LocationName，Coach.Source，S.Completed，S.DateScored HAVING（（（tblLocations.LocationName）=“Nashville”或（tblLocations.LocationName）=“Solon”或（tblLocations.LocationName）=“San Antonio”或（tblLocations.LocationName）=“Phoenix”）AND（（Coach.Source））=“主管”）AND（（S.Completed）= Yes）AND（（S.DateScored）＆gt; = [开始日期]和（S.DateScored）＆lt; = [结束日期]））;

Answer 1

您必须使用一些Access SQL函数：IIF()，Weekday()和DateAdd()。基本上，您必须找到日期weekday number（1-7，对应于周日 - 周六），然后添加相应的值以获取所有日期以返回周六日期：

SELECT [Coach].[LastName] & ", " & [Coach].[FirstName] AS CoachName, 
     Count(S.CallId) AS [CountOfSupervisors], tblLocations.LocationName,  
     IIF(Weekday(S.DateScored) = 7, S.DateScored,
     IIF(Weekday(S.DateScored) = 6, DateAdd('d', 1, S.DateScored),
     IIF(Weekday(S.DateScored) = 5, DateAdd('d', 2, S.DateScored),
     IIF(Weekday(S.DateScored) = 4, DateAdd('d', 3, S.DateScored),
     IIF(Weekday(S.DateScored) = 3, DateAdd('d', 4, S.DateScored),
     IIF(Weekday(S.DateScored) = 2, DateAdd('d', 5, S.DateScored),
     IIF(Weekday(S.DateScored) = 1, DateAdd('d', 6, S.DateScored), Null))))))) As EndOfWeek

FROM tblLocations INNER JOIN (tblScores AS S 
INNER JOIN tblEmployees AS Coach ON S.CoachId = Coach.ID) ON tblLocations.ID = S.LocationId 
WHERE (((tblLocations.LocationName IN ('Nashville','Solon','San Antonio','Phoenix') AND 
        ((Coach.Source)='Supervisor') AND ((S.Completed)=Yes) AND 
        ((S.DateScored)>=[Start Date] And (S.DateScored)<=[End Date]))

GROUP BY [Coach].[LastName] & ", " & [Coach].[FirstName], tblLocations.LocationName, 
     Coach.Source, S.Completed, 
     IIF(Weekday(S.DateScored) = 7, S.DateScored,
     IIF(Weekday(S.DateScored) = 6, DateAdd('d', 1, S.DateScored),
     IIF(Weekday(S.DateScored) = 5, DateAdd('d', 2, S.DateScored),
     IIF(Weekday(S.DateScored) = 4, DateAdd('d', 3, S.DateScored),
     IIF(Weekday(S.DateScored) = 3, DateAdd('d', 4, S.DateScored),
     IIF(Weekday(S.DateScored) = 2, DateAdd('d', 5, S.DateScored),
     IIF(Weekday(S.DateScored) = 1, DateAdd('d', 6, S.DateScored), Null)))))));

或者，这是一个不太详细的解决方案，由@HansUp标识，没有嵌套的IIF()语句：

SELECT [Coach].[LastName] & ", " & [Coach].[FirstName] AS CoachName, 
    Count(S.CallId) AS [CountOfSupervisors], tblLocations.LocationName,  
    DateAdd('d', IIf(S.DateScored Is Null, 0, 7 - Weekday(S.DateScored)), S.DateScored) As EndOfWeek

FROM tblLocations INNER JOIN (tblScores AS S 
INNER JOIN tblEmployees AS Coach ON S.CoachId = Coach.ID) ON tblLocations.ID = S.LocationId 
    WHERE (((tblLocations.LocationName IN ('Nashville','Solon','San Antonio','Phoenix') AND 
    ((Coach.Source)='Supervisor') AND ((S.Completed)=Yes) AND 
    ((S.DateScored)>=[Start Date] And (S.DateScored)<=[End Date]))

GROUP BY [Coach].[LastName] & ", " & [Coach].[FirstName], tblLocations.LocationName, 
    Coach.Source, S.Completed, 
    DateAdd('d', IIf(S.DateScored Is Null, 0, 7 - Weekday(S.DateScored)), S.DateScored);

您会注意到我调整了一些代码。您可以将所有HAVING语句移动到WHERE子句中（表示聚合时使用HAVING - Count，Sum，Avg，First，Last）。此外，您可以将IN()子句用于多个OR条件。希望这有效！

Access 2007：如何进行周末开始和周末，并在结果中显示周结束日期

1 个答案: