Question

我的数据库中有以下表格

|id|name |company_id|role           |
|1 |test1|11        |READADMIN      |
|2 |test2|11        |WRITEADMIN     |
|3 |test3|11        |READWRITEADMIN |
|4 |test4|12        |READADMIN      |
|5 |test5|12        |WRITEADMIN     |
|6 |test6|12        |READWRITEADMIN |
|7 |test6|11        |READADMIN      |
|8 |test7|13        |READADMIN      |
|9 |test8|12        |READADMIN      |
|10|test9|12        |READADMIN      |

我的目标是提取具有相同READADMIN角色company_id的所有管理员，此用户的数量应该超过1。

总的来说，我希望得到以下结果：

|id|name |company_id|role     |
|1 |test1|11        |READADMIN|
|7 |test6|11        |READADMIN|
|4 |test4|12        |READADMIN|
|9 |test8|12        |READADMIN|
|10|test9|12        |READADMIN|

我已在下方创建了选择，但我不确定其准确性和效果：

SELECT id, name, company_id, role
FROM  admin
WHERE  company_id IN(SELECT CO.id 
FROM company CO 
       join admin AU 
       ON CO.id = AU.company_id 
WHERE  role = 'READADMIN'
GROUP  BY CO.id 
HAVING Count(AU.id) > 1) 
AND role = 'READADMIN';

了解上述任务的最佳方法会很好。

Answer 1

我想这会工作：

SELECT DISTINCT id, name, company_id, role 
FROM admin WHERE role='READADMIN' GROUP BY CO.id

我不确定你的意思。我从您的问题中理解的是，您希望让所有用户认为他们的角色是＆＃39; READADMIN＆＃39;而且你不希望结果中有任何重复。

Answer 2

SELECT a.*
FROM admin a
WHERE a.role = 'READADMIN'
AND EXISTS ( SELECT 'a'
             FROM admin a2
             WHERE a2.role = a.role
             AND a2.company_id = a.company_id
             AND a2.id <> a.id
            )

Answer 3

为什么不：

SELECT id, name, company_id, role
FROM  admin
WHERE role = 'READADMIN'
GROUP  BY company_id 
HAVING Count(company_id) > 1 
   ;

Answer 4

以下代码段应仅授予对表的一次访问权限，更好地检查自己的计划。

select id, 
       name, 
       company_id, 
       role
  from (
       select id, 
              name, 
              company_id, 
              role, 
              count(distinct id) over (partition by company_id) as cn
         from admin
        where role = 'READADMIN'
       )
 where cn > 1;

Answer 5

我会做这样的事情。如果你已经有一个实际的表，显然你不需要with：

with admin as
(select 1 id,'test1' name,11 company_id, 'READADMIN' role from dual
union
select 2 id,'test2' name,11 company_id, 'WRITEADMIN' role from dual
union
select 3 id,'test3' name,11 company_id, 'READWRITEADMIN' role from dual
union
select 4 id,'test4' name,12 company_id, 'READADMIN' role from dual
union
select 5 id,'test5' name,12 company_id, 'WRITEADMIN' role from dual
union
select 6 id,'test6' name,12 company_id, 'READWRITEADMIN' role from dual
union
select 7 id,'test6' name,11 company_id, 'READADMIN' role from dual
union
select 8 id,'test7' name,13 company_id, 'READADMIN' role from dual
union
select 9 id,'test8' name,12 company_id, 'READADMIN' role from dual
union
select 10 id,'test9' name,12 company_id, 'READADMIN' role from dual)

select admin.id, admin.name, admin.company_id, admin.role
from admin 
inner join 
(select company_id, role 
from admin
where role = 'READADMIN'
group by company_id, role having count(*) > 1) grouped
on admin.company_id = grouped.company_id
and admin.role = grouped.role;

当特定列匹配多次时，提取所有行

5 个答案: