Question

#include <iostream>
#include <fstream>

using namespace std;

class Jung
{

public:
    int c1;
    int c2;
    int c3;
    int c4;
    int c5;
    int c6;
    friend Jung operator+(Jung n1, Jung l1);
    friend Jung operator*(Jung n2, Jung l2);
    friend ostream &operator<<(ostream &in, Jung n);
    friend istream &operator>>(istream &out, Jung &n);

};

Jung operator+(Jung n1, Jung l1){
     Jung nuoseklus;
     nuoseklus.c5=(1/((1/n1.c1)+(1/n1.c2)+(1/n1.c3)));
     return nuoseklus;
}
Jung operator*(Jung n2, Jung l2){
    Jung lygiagretus;
    lygiagretus.c6=n2.c4;
    return lygiagretus;
}
istream &operator>>(istream &in, Jung &n){
    in >> n.c1>>n.c2>>n.c3>>n.c4;
    return  in;
}
ostream &operator<<(ostream &out, Jung n){
    out << n.c5<<n.c6;
    return out;
}
int main() {
    Jung n,i,j;
    ifstream myfile("TadasVagonis_EIf_14-2_variantas_03.txt");
    cin>>i.c5>>j.c6;
    n=i+j;
    cout<<n<<endl;
    return 0;
}

我有一个文件，我需要从中读取4个数字，在函数operator +和operator *中使用它。第一个函数中的公式是好的，在operator *中我只需要它有c4值。我的最终答案应该是来自运算符+的值加上运算符*的值。因为英语不好，很难解释。

Answer 1

外部功能的签名是错误的。

应该是

Jung Jung::operator+(Jung RHS){
...
}

Jung Jung::operator*(Jung RHS){
...
}

等等。

之后尝试。希望你能实现你想要的目标

Answer 2

请编译代码并尝试理解您可以实现的特定行和其余程序的注释。

class Jung
    {    
    public:
        int c1, c2;
        Jung()
        {
          // defult constroctor
        }; 
        Jung(int tempa, int tempb)
        {
            c1 = tempa;
            c2 = tempb;
        }

        //now we will do operator overloading
        Jung operator+(Jung RHS)
        {
            c1 = RHS.c1;
            c2 = RHS.c2;
            return (*this); // read more about this pointer
        }
        friend ostream& operator<< (ostream &myOut, Jung &Rhs); // to inform the class thta this is a frind function    
};

    ostream& operator<< (ostream &myOut, Jung &Rhs)
    {
        myOut<<"value for C1 is :"<<Rhs.c1;
        myOut<<"\nValue for C2 is :"<<Rhs.c2;
        return myOut;   
    }

int main()
{
    Jung obj1(10,20);
    Jung obj2(30,40);
    Jung obj3;
    obj3 = obj1 + obj2; //Jung operator+(Jung RHS) will get called
    cout<<obj3; // ostream &operator<<(ostream &myOut, Jung &Rhs) will get called
    return 0;
}

C ++。从文件到功能，主要是cin

2 个答案: