如何在SQL Server中保持连接到第一行

时间:2015-04-03 09:02:21

标签: sql sql-server left-join

如何离开连接两个表,从第二个表中只选择第一行? first match

我的问题是跟进: SQL Server: How to Join to first row 我使用了那个帖子中建议的查询。

CREATE TABLE table1(
  id INT NOT NULL
);
INSERT INTO table1(id) VALUES (1);
INSERT INTO table1(id) VALUES (2);
INSERT INTO table1(id) VALUES (3);
GO

CREATE TABLE table2(
  id INT NOT NULL
, category VARCHAR(1)
);
INSERT INTO table2(id,category) VALUES (1,'A');
INSERT INTO table2(id,category) VALUES (1,'B');
INSERT INTO table2(id,category) VALUES (1,'C');
INSERT INTO table2(id,category) VALUES (3,'X');
INSERT INTO table2(id,category) VALUES (3,'Y');
GO

------------------
SELECT 
table1.* 
,FirstMatch.category
FROM table1

CROSS APPLY (
    SELECT TOP 1 
    table2.id
    ,table2.category   
    FROM table2 
    WHERE table1.id = table2.id
    ORDER BY id
    )
    AS FirstMatch

但是,通过此查询,我获得内部联接结果。我想离开加入结果。期望结果中的tabel1.id应为'2',为NULL。怎么做?

4 个答案:

答案 0 :(得分:4)

使用row_numberleft join

with cte as(

select id,
       category,
       row_number() over(partition by id order by category) rn
       from table2
)
select t.id, cte.category
from table1 t
left outer join cte 
on t.id=cte.id and cte.rn=1

<强>输出:

id  category
1   A
2   (null)
3   X

SQLFIDDLE DEMO

答案 1 :(得分:3)

select table1.id, 
(SELECT TOP 1 category FROM table2 WHERE table2.id=table1.id ORDER BY category ASC) AS category
FROM table1

答案 2 :(得分:1)

SELECT    table1.id ,table2.category 
FROM table1 Left join table2
on table1.id = table2.id
where table2.category = ( select top 1 category  from table2 t where table1.id = t.id) 
OR table2.category is NULL 

答案 3 :(得分:0)

t-clausen.dk的注释之后执行此操作:

CROSS APPLY更改为OUTER APPLY