我想解析一个自定义模板文件,但仍然在使用正则表达式。
我想解析以下文件:
@foreach(($ones) as $one)
@foreach($twos as $two)
multiline content
@endforeach
@endforeach
@foreach($three as $three)
@other_expression
@end_other_expression
@endforeach
结果应为:
<?php foreach(($ones) as $one) { ?>
<?php foreach ($twos as $two) { ?>
multiline content
<?php } ?>
<?php } ?>
<?php foreach($threes as $three) { ?>
@other_expression
@end_other_expression
<?php } ?>
取代@endforeach相当容易。我用这段代码做了:
$pattern = '/@endforeach/'
$replacement = '<?php } ?>';
$contents = preg_replace($pattern, $replacement, $contents);
现在我需要用以下代码替换我试过的@foreach部分:
$pattern = '/@foreach\(([^.]+)\)\\n/';
$replacement = '<?php foreach($1) { ?>';
$contents = preg_replace($pattern, $replacement, $contents);
问题是此模式无法识别我的@foreach()语句的结尾。新行的\ n不起作用。我不能使用右括号,因为foreachhead内可能有多个支架。
我愿意接受任何建议。
提前致谢。
答案 0 :(得分:2)
您可以连续使用2个正则表达式来执行此操作:
<?php
$str = "@foreach((\$ones) as \$one)\n\n @foreach(\$twos as \$two)\n\n multiline content\n\n @endforeach\n\n@endforeach\n\n@foreach(\$three as \$three)\n\n @other_expression\n\n @end_other_expression\n\n@endforeach>";
$result = preg_replace("/\\@endforeach/", "<?php } ?>", preg_replace("/\\@foreach(.*)/", "<?php foreach$1 { ?>", $str));
print $result;
?>
输出:
<?php foreach(($ones) as $one) { ?>
<?php foreach($twos as $two) { ?>
multiline content
<?php } ?>
<?php } ?>
<?php foreach($three as $three) { ?>
@other_expression
@end_other_expression
<?php } ?>