Question

Oracle Database 11g R2 11.2.0.1 SE1

考虑下表有3行的地址

ROW1 ：aaaaaaaaaaaaaaaaaaaaaaaaaaCRLFbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbCRLFcccccccccccccccCRLFddddd
ROW2 ：eeeeCRLFffffffffffffgggggggghCRLF
ROW3 ：iiCRLFjjjjjjjjjjkkkCRLF

我需要根据以下条件分割字符串
条件1 ：将字符串拆分为CRLF 条件2 ：如果拆分字符串的长度大于10，则将该字符串拆分为10个字符的长度。

注意：数据的长度不固定。

结果： -
的 ADDRESS
ROW1 ：aaaaaaaaaa       AAAAAAAAAA
aaaaaCRLF
      bbbbbbbbbb
      bbbbbbbbbb
      bbbbbbbbbb
      bbCRLF
      CCCCCCCCCC
      cccccCRLF
      DDDDD
ROW2 ：eeeeCRLF
      ffffffffff
      ffgggggggg
      hCRLF
ROW3 ：iiCRLF
      jjjjjjjjjj
      kkkCRLF

Answer 1

此答案基于此处的技术：https://stackoverflow.com/a/29338715/4311

首先，我们将在名为data的CTE中设置您的样本数据。然后，查询根据CRLF的出现将此文本拆分为行，这些行为给出了data2。

然后我们在结果字符串中每10个字符添加一个CRLF，这样就可以得到data3。最后，我们再次重复原始流程，根据CRLF将文本拆分为行，产生data4。

with data as
(select 'row1' rowval, 'aaaaaaaaaaaaaaaaaaaaaaaaaa' || chr(13) || chr(10) || 'bbbbbbbbbbbbbbbbbbbbbbbbbbbbbbbb' || chr(13) || chr(10) || 'ccccccccccccccc' || chr(13) || chr(10) || 'ddddd' txt from dual union all
 select 'row2' rowval, 'eeee' || chr(13) || chr(10) || 'ffffffffffffggggggggh' || chr(13) || chr(10) txt from dual union all
 select 'row3' rowval, 'ii' || chr(13) || chr(10) || 'jjjjjjjjjjkkk' || chr(13) || chr(10) txt from dual
)
select rowval,
       txt
  from (select rowval,
               trim(regexp_substr(txt, '[^' || CHR(13)||CHR(10) || ']+', 1, lines.column_value)) txt
          from (select rowval,
                       regexp_replace(txt,
                                      '(.{10})',
                                      '\1' || CHR(13) || CHR(10)) txt
                  from (SELECT rowval,
                               trim(regexp_substr(data.txt, '[^' || CHR(13)||CHR(10) || ']+', 1, lines.column_value)) txt
                          FROM data,
                               TABLE(CAST(MULTISET(SELECT LEVEL
                                                     FROM dual
                                                   CONNECT BY instr(data.txt, CHR(13)||CHR(10), 1, LEVEL - 1) > 0
                                                  ) AS sys.odciNumberList
                                         )
                                    ) lines
                        ) data2
               ) data3,
               TABLE(CAST(MULTISET(SELECT LEVEL
                                             FROM dual
                                           CONNECT BY instr(data3.txt, CHR(13)||CHR(10), 1, LEVEL - 1) > 0
                                          ) AS sys.odciNumberList
                                 )
                         ) lines
       ) data4
 where txt is not null
ORDER BY rowval, txt;

此查询产生我们：

ROWV TXT
---- ------------
row1 aaaaaa
row1 aaaaaaaaaa
row1 aaaaaaaaaa
row1 bb
row1 bbbbbbbbbb
row1 bbbbbbbbbb
row1 bbbbbbbbbb
row1 ccccc
row1 cccccccccc
row1 ddddd
row2 eeee
row2 ffffffffff
row2 ffgggggggg
row2 h
row3 ii
row3 jjjjjjjjjj
row3 kkk

REG：拆分CRLF数据和10个字符长度（SQL，PL / SQL）

1 个答案: