iOS拍摄多个屏幕截图

时间:2015-04-03 02:34:04

标签: ios xcode video camera

我有一个包含视频的 NSURL ,我想每秒十次录制该视频的一帧。我有代码可以捕获我的播放器的图像,但是我无法将其设置为每秒捕获10帧。我正在尝试这样的东西,但是它返回了视频的相同初始帧,正确的次数?这就是我所拥有的:

AVAsset *asset = [AVAsset assetWithURL:videoUrl];
CMTime vidLength = asset.duration;
float seconds = CMTimeGetSeconds(vidLength);
int frameCount = 0;
for (float i = 0; i < seconds;) {
    AVAssetImageGenerator *imageGenerator = [[AVAssetImageGenerator alloc]initWithAsset:asset];
    CMTime time = CMTimeMake(i, 10);
    CGImageRef imageRef = [imageGenerator copyCGImageAtTime:time actualTime:NULL error:NULL];
    UIImage *thumbnail = [UIImage imageWithCGImage:imageRef];
                                CGImageRelease(imageRef);
NSString* filename = [NSString stringWithFormat:@"Documents/frame_%d.png", frameCount];
NSString* pngPath = [NSHomeDirectory() stringByAppendingPathComponent:filename];

[UIImagePNGRepresentation(thumbnail) writeToFile: pngPath atomically: YES];
frameCount++;
i = i + 0.1;
}

但是我没有在视频的当前时间获取帧,而是获得初始帧?

如何每秒10次获取视频帧?

感谢您的帮助:)

2 个答案:

答案 0 :(得分:13)

您正在获取初始帧,因为您尝试使用浮点值创建CMTime:

CMTime time = CMTimeMake(i, 10);

由于 CMTimeMake 函数将 int64_t 值作为第一个参数,因此您的浮点值将四舍五入为整数,并且您将得到不正确的结果。

让我们稍微改变你的代码:

1)首先,您需要查找需要从视频中获取的总帧数。你写道,你需要每秒10帧,所以代码将是:

int requiredFramesCount = seconds * 10;

2)接下来,您需要找到一个值,该值将在每一步增加您的CMTime值:

int64_t step = vidLength.value / requiredFramesCount;

3)最后,您需要将requestedTimeToleranceBefore和requestedTimeToleranceAfter设置为kCMTimeZero,以便在精确时间获取帧:

imageGenerator.requestedTimeToleranceAfter = kCMTimeZero;
imageGenerator.requestedTimeToleranceBefore = kCMTimeZero;

以下是您的代码的样子:

CMTime vidLength = asset.duration;
float seconds = CMTimeGetSeconds(vidLength);

int requiredFramesCount = seconds * 10;
int64_t step = vidLength.value / requiredFramesCount;

int value = 0;

for (int i = 0; i < requiredFramesCount; i++) {

    AVAssetImageGenerator *imageGenerator = [[AVAssetImageGenerator alloc]initWithAsset:asset];
    imageGenerator.requestedTimeToleranceAfter = kCMTimeZero;
    imageGenerator.requestedTimeToleranceBefore = kCMTimeZero;

    CMTime time = CMTimeMake(value, vidLength.timescale);

    CGImageRef imageRef = [imageGenerator copyCGImageAtTime:time actualTime:NULL error:NULL];
    UIImage *thumbnail = [UIImage imageWithCGImage:imageRef];
    CGImageRelease(imageRef);
    NSString* filename = [NSString stringWithFormat:@"Documents/frame_%d.png", i];
    NSString* pngPath = [NSHomeDirectory() stringByAppendingPathComponent:filename];

    [UIImagePNGRepresentation(thumbnail) writeToFile: pngPath atomically: YES];

    value += step;
}

答案 1 :(得分:2)

使用CMTimeMake(A, B)存储有理数,精确分数A / B秒,此函数的第一个参数采用int值。对于20秒的视频,您将在循环的最后一次迭代中捕获具有时间((int)19.9)/ 10 = 1.9秒的帧。使用CMTimeMakeWithSeconds(i, NSEC_PER_SEC)功能解决此时间问题。