Question

我正在尝试选择记录与另一条记录共享字段值的记录，但我尝试的查询只返回一次。例如，在此表中：

COUNTRY         LANGUAGE
Mexico          Spanish
Portugal        Portuguese
Russia          Russian
Spain           Spanish
Thailand        Thai
United Kingdom  English
United States   English

...我想回来：

COUNTRY         LANGUAGE
Mexico          Spanish
Spain           Spanish
United Kingdom  English
United States   English

使用：

SELECT * FROM `table` GROUP BY `language` HAVING COUNT(language) > 1

我只得到：

COUNTRY         LANGUAGE
Spain           Spanish
United Kingdom  English

我在哪里错了？

Answer 1

找到解决方案：

SELECT * FROM `TABLE` WHERE `language` IN (
    SELECT * GROUP BY `language` HAVING COUNT(primary_language) > 1
)

Answer 2

您需要将其分解为两个步骤。获取子选择中的语言列表，然后获取行：

SELECT * FROM country_language where language in（SELECT language FROM country_language GROUP BY language HAVING COUNT（*）＆gt; 1）

Answer 3

试试这个

SELECT COUNTRY，LANGUAGE FROM table WHERE LANGUAGE IN（SELECT table SELECT BY language GROUP BY {{1}} COUNT（语言）＆gt; 1）;

Answer 4

您需要一个子查询，它返回多个国家/地区的语言集。然后选择语言在该集合中的所有行：

SELECT *
FROM `table`
WHERE language IN
(
  SELECT language FROM `table` GROUP BY `language` HAVING COUNT(*) > 1
)

Answer 5

我不是那么有经验，但这应该可以做到！

SELECT Country
from (SELECT Country, count(Lang) as Langs
FROM Land
Group by Lang) as table2
WHERE table2.Langs!=1

MySQL选择字段中重复的位置，而不是返回所有记录

5 个答案: