Question

我的任务是将v1连接到v2，功能my_strcat()必须是void。如何使用void函数返回连接的字符串？

int main(void){
    char v1[16], v2[16];
    int i1, i2;
    printf("Enter First Name: \n");
    scanf("%s", v1);
    printf("Enter Last Name: \n");
    scanf("%s", v2);
    i1 = my_strlen(v1);
    i2 = my_strlen(v2);
    printf("len: %3d - string: %s \n", i1, v1);
    printf("len: %3d - string: %s \n", i2, v2);
    my_strcat(v1, v2);
    printf("Concatenated String: %s \n", v1);
    return 0;
}

void my_strcat (char s1[], char s2[]){
    int result[16];
    int i = 0;
    int j = 0;
    while(s1[i] != '\0'){
        ++i;
        result[i]= s1[i];
    }
    while(s2[j] != '\0'){
        ++j;
        result[i+j] = s2[j];
    }
    result[i+j] = '\0';
}

Answer 1

void my_strcat (char s1[], char s2[],char result[]){
    int result[16];
    int i = 0;
    int j = 0;
    while(s1[i] != '\0'){
        result[i]= s1[i];
        ++i;
    }
    while(s2[j] != '\0'){
        result[i+j] = s2[j];
        ++j;
    }
    result[i+j] = '\0';
}

你可以这样做......我的main（）声明第三个结果字符串，其大小是大小（v1）+大小（v2）+1

char result[33];
my_strcat(v1,v2,result);

输出：

Enter First Name: avinash
Enter Last Name: pandey
len:   7 - string: avinash 
len:   6 - string: pandey 
Concatenated String: avinashpandey

C中的连接字符串

1 个答案: