使用数据库中的数据构建排名系统

时间:2010-05-31 07:04:29

标签: php

我正在建立一个排名系统,从数据库中获取数据(总数)并将它们从最高到最低排列。这是代码:

$data = array(
  'A'=>19,'B'=>18,'C'=>17,'D'=>17,'E'=>16,'F'=>15
);
//Populate the arrays with data from mysql
/*
--
-- Table structure for table `data`
--

CREATE TABLE IF NOT EXISTS `data` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `totals` int(11) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=501 ;

--
-- Dumping data for table `data`
--

INSERT INTO `data` (`id`, `totals`) VALUES
(1, 468),
(2, 450),
(3, 400),
(4, 419),
(5, 400),
(6, 400),
(7, 500),
(8, 489),
(9, 412),
(10, 385);

*/
$rank = 0;
$lastScore = PHP_INT_MAX;
foreach( $data as $name=>$score ) {
  if ( $lastScore !== $score ) {
    $lastScore = $score;
    $rank += 1;
  }
  printf("%s %d (%d)\n", $name, $score, $rank);
}

我想用一种方法用数据库中存储的值填充变量($ data),我该怎么做?。

2 个答案:

答案 0 :(得分:1)

Undgerman - 您必须连接到MySQL数据库:

http://us2.php.net/manual/en/function.mysql-connect.php

然后选择您的数据库:

http://us2.php.net/manual/en/function.mysql-select-db.php

然后执行MySQL查询:

http://us2.php.net/manual/en/function.mysql-query.php

然后获取结果:

http://us2.php.net/manual/en/function.mysql-fetch-assoc.php


实施例

<?php
mysql_connect( 'host', 'username', 'password' ); 
mysql_select_db( 'database' );

$result = mysql_query( 'SELECT * FROM `data`' );
$data = mysql_fetch_assoc( $result );
?>

意识到您可以在查询中对这些数据进行排序:

$result = mysql_query( 'SELECT * FROM `data` ORDER BY `totals`' );

答案 1 :(得分:1)

我现在已经完成了简单的排名系统,我想我应该分享我的代码。从pear获取db包,项目需要它。

<?php
require_once 'DB.php';

$dsn = array(
    'phptype'  => 'mysql',
    'username' => 'root',
    'password' => '',
    'hostspec' => 'localhost',
    'database' => 'rm-db',
);

$options = array(
    'debug'       => 2,
    'portability' => DB_PORTABILITY_ALL,
);

$db =& DB::connect($dsn, $options);
if (PEAR::isError($db)) {
    die($db->getMessage());
}

$data =& $db->getCol('SELECT  totals FROM data order by totals desc');

if (PEAR::isError($data)) {
    die($data->getMessage());
}

//print_r($data);

//Populate the arrays with data from mysql and arrange in descending order.
//SELECT * FROM data order by totals desc
/*
--
-- Table structure for table `data`
--

CREATE TABLE IF NOT EXISTS `data` (
  `id` int(11) NOT NULL AUTO_INCREMENT,
  `totals` int(11) NOT NULL,
  PRIMARY KEY (`id`)
) ENGINE=MyISAM  DEFAULT CHARSET=latin1 AUTO_INCREMENT=501 ;

--
-- Dumping data for table `data`
--

INSERT INTO `data` (`id`, `totals`) VALUES
(1, 468),
(2, 450),
(3, 400),
(4, 419),
(5, 400),
(6, 400),
(7, 500),
(8, 489),
(9, 412),
(10, 385);

*/
$rank = 0;
$lastScore = PHP_INT_MAX;
foreach( $data as $name=>$score ) {
  if ( $lastScore !== $score ) {
    $lastScore = $score;
    $rank += 1;
  }
  printf("%s %d (%d)\n", $name, $score, $rank);
}