Question

我有一个表格，下面的结构

PickupPointCode     LocationCode        ClientCode

    1           LOC1            Client1/Client2
    2           LOC2            Client3/Client4/Client5
    3           LOC3            Client6

所需的输出

PickupPointCode     LocationCode        ClientCode

1           LOC1            Client1
1           LOC1            Client2
2           LOC2            Client3
2           LOC2            Client4
2           LOC2            Client5
3           LOC3            Client6

使用SQL serevr 2005我编写了以下查询来完成这项工作

;WITH cte AS (    
SELECT         
 PickupPointCode
 ,LocationCode
 ,CAST('<i>' + REPLACE(ClientCode, '/', '</i><i>') + '</i>' AS XML) AS ClientCodes   
FROM <TABLE NAME>)
SELECT     
 PickupPointCode
 ,LocationCode
 ,x.i.value('.', 'VARCHAR(MAX)') AS ClientCode
FROM cte
CROSS APPLY ClientCodes.nodes('//i') x(i)

但现在我必须使用 SQL SERVER 2000 做同样的事情。我怎么能这样做？

谢谢

Answer 1

基本思想是将每行乘以与CLIENT一样多的次数。然后，提取字符串的相应部分。

查看一些适用于SQL2005 + here的示例查询您将需要使用包含SQL2000中的序列号的额外表。

CREATE TABLE dbo.Numbers
(
   N INT NOT NULL PRIMARY KEY
);
GO

DECLARE @rows AS INT;
SET @rows = 1;

INSERT INTO dbo.Numbers VALUES(1);
WHILE(@rows <= 1000)
BEGIN
   INSERT INTO dbo.Numbers SELECT N + @rows FROM dbo.Numbers;
   SET @rows = @rows * 2;
END

这是您可以加入的数字表。以下是适用于SQL 2000的查询。

SELECT PickupPointCode, LocationCode,
    SUBSTRING(ClientCode, Numbers.N,
        CHARINDEX('/', ClientCode + '/', Numbers.N) - Numbers.N) AS ClientCode 
    FROM <TABLE_NAME> 
    JOIN Numbers ON Numbers.N <= DATALENGTH(ClientCode) + 1  
    AND SUBSTRING('/' + ClientCode, Numbers.N, 1) = '/'

如何使用SQL SERVER 2000（没有游标）对字符串执行拆分操作并附加到特定ID？

1 个答案: