如何创建一个有效的递归函数 - 它将采用输入源 - 可能是1000行的长度。进入一个压缩的数组。递归函数可能需要某种查找来确定是否有一个高于当前员工ID的经理。
我正在尝试构建一个可能需要在数组中使用整个关系管理树的应用程序。
我需要设计一种方法来在输入数据源上创建递归函数,以将其映射到整理的输出数组。
//the input data may look something like this
[{
"employeeId": "A1",
"managerId": "B1",
"employeeRole": "Sales0",
"managerRole": "Sales1"
}, {
"employeeId": "B1",
"managerId": "C1",
"employeeRole": "Sales1",
"managerRole": "Sales2"
}, {
"employeeId": "C1",
"managerId": "D1",
"employeeRole": "Sales2",
"managerRole": "Sales3"
}, {
"employeeId": "D1",
"managerId": "",
"employeeRole": "Sales3",
"managerRole": "Sales4"
}]
//create a final output array like this
[
"level1id": "A1",
"level2id": "B1",
"level3id": "C1",
"level4id": "D1",
]
我在这个阶段的裸骨pseduo代码是这样的
void myMethod(String employeeId, String[] rawData, Map < String, String > dataMap) {
//employeeId -- child id
//rawData - from feed
//dataMap - the array being built to contain ALL relationships from grand child, parent, grandparent.
getManager(employeeId, rawData) {
//find the manager of the current employeeid
//managerData[0] - manager id
//managerData[1] - manager role
return managerData;
}
managerData = getManager(employeeId, rawData);
managerId = managerData[0];
managerRole = managerData[1];
dataMap.put(managerData[1], managerData[0]);
// like [{"customerLevel1" : "SKDOL2"}]
//if there is no manager id - the grandparent manager has been found
if (managerId !== null)
return;
else {
//this employeeid has a manager above them - loop through again until the grandparent is found (employee id with no manager)
myMethod(managerId, rawData, dataMap);
return;
}
}
答案 0 :(得分:1)
你需要做一些工作来阅读数据并解析它并构建你的数据结构,但类似关系的类似于你应该需要的东西。
class Person {
private final String id;
public Person(String id) {
this.id = id;
}
public String getId() {
return id;
}
}
class Employee extends Person {
private final String managerId;
public String getManagerId() {
return managerId;
}
public Employee(String id, String managerId ) {
super(id);
this.managerId = managerId;
}
}
class Manager extends Employee {
private final String role;
public String getRole() {
return role;
}
public Manager(String id, String managerId, String role ) {
super(id, managerId);
this.role = role;
}
}
/**
* Use this to look up any person.
*
* Put ALL employees an managers in here as you read them.
*/
Map<String, Employee> personLookup = new HashMap<>();
答案 1 :(得分:1)
我假设你的输入数据格式是json,所以你需要json.jar。
import java.util.ArrayList;
import java.util.HashMap;
import java.util.List;
import org.json.JSONArray;
import org.json.JSONObject;
public class OrgnizationTree {
HashMap<String, ArrayList<Employee>> jsonDataMap = new HashMap<String, ArrayList<Employee>>();
HashMap<String, Employee> employeeMap = new HashMap<String, Employee>();
Employee root;
public void buildTree(String jsonData) throws Exception {
JSONArray array = new JSONArray(jsonData);
for (int i = 0; i < array.length(); i++) {
JSONObject object = (JSONObject) array.get(i);
String employeeId = object.get("employeeId").toString();
String managerId = object.get("managerId").toString();
if (managerId == null || managerId.isEmpty()) {
root = new Employee(employeeId, null);
} else {
Employee subordinate = new Employee(employeeId);
if (jsonDataMap.containsKey(managerId)) {
jsonDataMap.get(managerId).add(subordinate);
} else {
ArrayList<Employee> subordinates = new ArrayList<Employee>();
subordinates.add(subordinate);
jsonDataMap.put(managerId, subordinates);
}
}
}
for (Employee subordinate : jsonDataMap.get(root.getId())) {
root.addSubordinate(subordinate);
subordinate.setManager(root);
employeeMap.put(root.getId(), root);
buildSubTree(subordinate);
}
}
public void buildSubTree(Employee manager) {
List<Employee> subordinates = jsonDataMap.get(manager.getId());
if (subordinates != null) {
for (Employee subordinate : subordinates) {
subordinate.setManager(manager);
manager.addSubordinate(subordinate);
buildSubTree(subordinate);
}
}
employeeMap.put(manager.getId(), manager);
}
public Employee getManager(String employeeId) {
Employee employee = employeeMap.get(employeeId);
Employee manager = employee.getManager();
return manager;
}
public Employee getEmployee(String employeeId) {
return employeeMap.get(employeeId);
}
public Employee getRoot() {
return root;
}
public class Employee {
String id;
Employee manager;
List<Employee> subordinates;
Integer level;
Employee(String id, Employee manager) {
this.id = id;
this.manager = manager;
if (manager == null) {
level = 0;
} else {
level = manager.level + 1;
}
}
Employee(String id) {
this.id = id;
}
public void addSubordinate(Employee subordinate) {
if (subordinates == null) {
subordinates = new ArrayList<Employee>();
}
subordinates.add(subordinate);
}
public String getId() {
return this.id;
}
public Employee getManager() {
return manager;
}
public void setManager(Employee manager) {
this.manager = manager;
this.level = manager.level + 1;
}
}
public static void main(String[] args) throws Exception {
String jsonData = "[{'employeeId': 'A1', 'managerId': 'B1'}, {'employeeId': 'B1', 'managerId': 'C1'}, "
+ "{'employeeId': 'C1', 'managerId': 'D1'}, {'employeeId': 'D1', 'managerId': ''}]";
OrgnizationTree t = new OrgnizationTree();
t.buildTree(jsonData);
System.out.println(t.getManager("A1").getId());
System.out.println(t.getEmployee("A1").getManager().getId());
System.out.println(t.getRoot().getId());
}
}