Question

我尝试使用asp.net 3.5创建一个JSON Web服务，结果以xml形式返回：

<string xmlns="http://.../">
[{"HatId":9,"HatAdi":"SARISU - GÜZELOBA","LevhaAciklama":"KL08"}]
</string>

我使用了LINK示例，我意识到该示例也作为xml返回。

    [WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public string HatlarJSON(String HatAdi)
    {

        Hatlar[] allRecords = null;
        string sql = "SELECT * FROM Table";
        SqlConnection con = new SqlConnection("Data Source="ip";Initial Catalog="";User Id="";Password="";Integrated Security=False");
        con.Open();
        using (var command = new SqlCommand(sql, con))
        {
            using (var reader = command.ExecuteReader())
            {
                var list = new List<Hatlar>();
                while (reader.Read())
                    list.Add(new Hatlar { HatId = reader.GetInt32(0), HatAdi = reader.GetString(1), LevhaAciklama = reader.GetString(2) });
                allRecords = list.ToArray();
            }
        }


        return new JavaScriptSerializer().Serialize(allRecords);


    }

如何在没有xml的情况下返回解决方案？

有人有想法吗？

Answer 1

[WebMethod]
    [ScriptMethod(ResponseFormat = ResponseFormat.Json)]
    public void HatlarJSON(String HatAdi)
    {

        Hatlar[] allRecords = null;
        string sql = "SELECT * FROM Table";
        SqlConnection con = new SqlConnection("Data Source="ip";Initial Catalog="";User Id="";Password="";Integrated Security=False");
        con.Open();
        using (var command = new SqlCommand(sql, con))
        {
            using (var reader = command.ExecuteReader())
            {
                var list = new List<Hatlar>();
                while (reader.Read())
                    list.Add(new Hatlar { HatId = reader.GetInt32(0), HatAdi = reader.GetString(1), LevhaAciklama = reader.GetString(2) });
                allRecords = list.ToArray();
            }
        }

Context.Response.Write( Newtonsoft.Json.JsonConvert.SerializeObject(allRecords));
      //this is what I'm using


Context.Response.Write( JavaScriptSerializer().Serialize(allRecords)); //your code


    }

您的 webmethod 包含字符串类型，因此它会尝试将字符串作为响应返回。所以，我们需要将响应作为对象发送。

我也有同样的问题

从此处找到解决方案https://stackoverflow.com/a/5392932/2630817

JSON结果以XML格式返回

1 个答案: