假设我有一个包含以下信息的表:
FK | Field1 | Field2
=====================
3 | ABC | *NULL*
3 | *NULL* | DEF
有没有办法在表格上执行选择以获得以下内容
FK | Field1 | Field2
=====================
3 | ABC | DEF
由于
编辑:为了清晰起见,修复了field2名称
答案 0 :(得分:15)
汇总功能可以帮到你。聚合函数忽略NULLs
(至少在SQL Server,Oracle和Jet / Access上都是如此),因此您可以使用这样的查询(在SQL Server Express 2008 R2上测试):
SELECT
FK,
MAX(Field1) AS Field1,
MAX(Field2) AS Field2
FROM
table1
GROUP BY
FK;
我使用了MAX
,但是从GROUP BY
行中选择一个值的任何聚合都应该有效。
测试数据:
CREATE TABLE table1 (FK int, Field1 varchar(10), Field2 varchar(10));
INSERT INTO table1 VALUES (3, 'ABC', NULL);
INSERT INTO table1 VALUES (3, NULL, 'DEF');
INSERT INTO table1 VALUES (4, 'GHI', NULL);
INSERT INTO table1 VALUES (4, 'JKL', 'MNO');
INSERT INTO table1 VALUES (4, NULL, 'PQR');
结果:
FK Field1 Field2
-- ------ ------
3 ABC DEF
4 JKL PQR
答案 1 :(得分:6)
根据您未包含的某些数据规则,有几种方法,但这是使用您提供的内容的一种方式。
SELECT
t1.Field1,
t2.Field2
FROM Table1 t1
LEFT JOIN Table1 t2 ON t1.FK = t2.FK AND t2.Field1 IS NULL
另一种方式:
SELECT
t1.Field1,
(SELECT Field2 FROM Table2 t2 WHERE t2.FK = t1.FK AND Field1 IS NULL) AS Field2
FROM Table1 t1
答案 2 :(得分:3)
我有类似的问题。不同之处在于我需要对我返回的内容进行更多控制,因此我最终得到了一个简单明了但相当长的查询。以下是基于您的示例的简化版本。
select main.id, Field1_Q.Field1, Field2_Q.Field2
from
(
select distinct id
from Table1
)as main
left outer join (
select id, max(Field1)
from Table1
where Field1 is not null
group by id
) as Field1_Q on main.id = Field1_Q.id
left outer join (
select id, max(Field2)
from Table1
where Field2 is not null
group by id
) as Field2_Q on main.id = Field2_Q.id
;
这里的诀窍是第一个选择'main'选择要显示的行。然后每个字段有一个选择。正在加入的内容应该是'main'查询返回的所有相同值。
请注意,其他查询只需要为每个ID返回一行,否则您将忽略数据
答案 3 :(得分:2)
可能有更简洁的方法,但以下可能是一种方法:
SELECT t.fk,
(
SELECT t1.Field1
FROM `table` t1
WHERE t1.fk = t.fk AND t1.Field1 IS NOT NULL
LIMIT 1
) Field1,
(
SELECT t2.Field2
FROM `table` t2
WHERE t2.fk = t.fk AND t2.Field2 IS NOT NULL
LIMIT 1
) Field2
FROM `table` t
WHERE t.fk = 3
GROUP BY t.fk;
测试用例:
CREATE TABLE `table` (fk int, Field1 varchar(10), Field2 varchar(10));
INSERT INTO `table` VALUES (3, 'ABC', NULL);
INSERT INTO `table` VALUES (3, NULL, 'DEF');
INSERT INTO `table` VALUES (4, 'GHI', NULL);
INSERT INTO `table` VALUES (4, NULL, 'JKL');
INSERT INTO `table` VALUES (5, NULL, 'MNO');
结果:
+------+--------+--------+
| fk | Field1 | Field2 |
+------+--------+--------+
| 3 | ABC | DEF |
+------+--------+--------+
1 row in set (0.01 sec)
运行不带WHERE t.fk = 3
子句的相同查询,它将返回以下结果集:
+------+--------+--------+
| fk | Field1 | Field2 |
+------+--------+--------+
| 3 | ABC | DEF |
| 4 | GHI | JKL |
| 5 | NULL | MNO |
+------+--------+--------+
3 rows in set (0.01 sec)
答案 4 :(得分:1)
如果一行在field1列中具有值,而其他行具有空值,则此查询可能有效。
SELECT
FK,
MAX(Field1) as Field1,
MAX(Field2) as Field2
FROM
(
select FK,ISNULL(Field1,'') as Field1,ISNULL(Field2,'') as Field2 from table1
)
tbl
GROUP BY FK
答案 5 :(得分:0)
SELECT Q.FK
,ISNULL(T1.Field1, T2.Field2) AS Field
FROM (SELECT FK FROM Table1
UNION
SELECT FK FROM Table2) AS Q
LEFT JOIN Table1 AS T1 ON T1.FK = Q.FK
LEFT JOIN Table2 AS T2 ON T2.FK = Q.FK
如果有一个表,请写Table1而不是Table2
答案 6 :(得分:-1)
我的情况是我有一个这样的桌子
---------------------------------------------
|company_name|company_ID|CA | WA |
---------------------------------------------
|Costco | 1 |NULL | 2 |
---------------------------------------------
|Costco | 1 |3 |Null |
---------------------------------------------
我希望它像下面这样:
---------------------------------------------
|company_name|company_ID|CA | WA |
---------------------------------------------
|Costco | 1 |3 | 2 |
---------------------------------------------
大多数代码几乎相同:
SELECT
FK,
MAX(CA) AS CA,
MAX(WA) AS WA
FROM
table1
GROUP BY company_name,company_ID
唯一的区别是group by
,如果您将两个列名放入其中,则可以将它们成对分组。