如何将输出写入文件?我试过而不是process.stdout
使用fs.createWriteStream(temp + '/export2.json')
,但它没有用。
var rl = readline.createInterface({
input: fs.createReadStream(temp + '/export.json'),
output: process.stdout,
terminal: false
});
rl.on('line', function(line) {
rl.write(line);
});
答案 0 :(得分:3)
第313行:
Interface.prototype.write = function(d, key) {
if (this.paused) this.resume();
this.terminal ? this._ttyWrite(d, key) : this._normalWrite(d);
};
通过调用rl.write()
,您可以写入tty或调用_normalWrite()
,其定义在块之后。
Interface.prototype._normalWrite = function(b) {
// some code
// .......
if (newPartContainsEnding) {
this._sawReturn = /\r$/.test(string);
// got one or more newlines; process into "line" events
var lines = string.split(lineEnding);
// either '' or (concievably) the unfinished portion of the next line
string = lines.pop();
this._line_buffer = string;
lines.forEach(function(line) {
this._onLine(line);
}, this);
} else if (string) {
// no newlines this time, save what we have for next time
this._line_buffer = string;
}
};
输出被写入_line_buffer
。
第96行:
function onend() {
if (util.isString(self._line_buffer) && self._line_buffer.length > 0) {
self.emit('line', self._line_buffer);
}
self.close();
}
我们发现,_line_buffer
最终会被发送到line
个事件。这就是为什么你不能把输出写入writeStream的原因。要解决此问题,您只需在fs.openSync()
回调中使用fs.write()
和rl.on('line', function(line){})
打开文件即可。
示例代码:
var rl = readline.createInterface({
input: fs.createReadStream(temp + '/export.json'),
output: process.stdout,
terminal: false
});
fd = fs.openSync('filename', 'w');
rl.on('line', function(line) {
fs.write(fd, line);
});
答案 1 :(得分:1)
readline
不使用 output
选项写入文件。但是,您可以照常创建写入流并照常写入。
示例:
const { EOL } = require("os");
const rl = readline.createInterface({
input: fs.createReadStream(temp + '/export.json'),
});
const writeStream = fs.createWriteStream(temp + '/export2.json', { encoding: "utf8" })
rl.on('line', function(line) {
writeStream.write(`${line}${EOL}`);
});