Question

我有如下表格

SCHEME  BROKNO  BRANNO  ACCNO   TYPE    SCAMT   FUNAMT  MONTH
AFS       123    345    125635  RN       130     140    11
AFS       123    345    125635  RN       130     140    11
AFS       123    345    125635  RN       145     185    11
AFS       123    345    125635  RN       130     140    11
AFS       123    345    125635  RN       180     220    10
AFS       123    345    125635  RN       200     260    10
AFS       123    345    125635  RN       180     220    10
AFS       123    345    125635  RN       180     220    10

现在我必须根据月份列创建报告并基于组（SCHEME，BROKNO，BRANNO，ACCNO，TYPE）。

报告应该是

SCHEME BROKNO BRANNO ACCNO TYPE SUM(SCAMT) SUM(FUNAMT) MONTH11CNT   
AFS    123    345   125635 RN    535            605      4         

SUM(SCAMT) SUM(FUNAMT) MONTH11CNT 
740         920           4

我已尝试使用case语句，但我对所有记录组都有相同的计数。请有人给我一点想法。

Answer 1

看起来你只想按照计划，brokno，branno，accno，类型和月份进行分组：

select 
  scheme, brokno, branno, accno, type, month, 
  sum(scamt), sum(funamt), count(*) as monthcnt
from mytable
group by scheme, brokno, branno, accno, type, month;

编辑：如果要在列中显示月份，您必须事先知道几个月并相应地编写查询：

select 
  scheme, brokno, branno, accno, type,
  sum(case when month = 10 then scamt end) as month10scamt,
  sum(case when month = 10 then funamt end) as month10funamt,
  sum(case when month = 10 then 1 end) as month10cnt,
  sum(case when month = 11 then scamt end) as month11scamt,
  sum(case when month = 11 then funamt end) as month11funamt,
  sum(case when month = 11 then 1 end) as month11cnt
from mytable
where month in (10,11)
group by scheme, brokno, branno, accno, type;

Answer 2

您可以使用它来获得您想要的结果

SELECT 
  SCHEME,
  BROKNO,
  BRANNO,
  ACCNO,
  TYPE,
  SUM(SCAMT) As SCAMTTOTAL,
  SUM(FUNAMT) AS FUNAMTTOTAL,
  MONTH As MONTHNAME,
  COUNT(MONTH) AS MONTHCOUNT
FROM MyTABLE
GROUP BY
  SCHEME,
  BROKNO,
  BRANNO,
  ACCNO,
  TYPE,
  MONTH

如果您需要将结果放在一行中，那么只需将其转换为CTE并查询即可。

SQLFIDDLE

Answer 3

假设您想要计算每个月内的行数，一个解决方案是将月份纳入聚合：

select SCHEME, BROKNO, BRANNO, ACCNO, TYPE, MONTH,
       sum(SCAMT),
       sum(FUNAMT),
       Count(*) as MONTHCOUNT
from table
group by SCHEME, BROKNO, BRANNO, ACCNO, TYPE, MONTH

如何使用聚合函数获取SUM和COUNT

3 个答案: