Question

我有一个包含用户文化的用户表。我需要从时间文化中获得时间。如需参考，请参阅下表。

           UserCulture 
------------------------------------------
(UTC-12:00) International Date Line West
(UTC-08:00) Baja California
(UTC+05:30) Chennai, Kolkata, Mumbai, New Delhi
(UTC+08:00) Kuala Lumpur, Singapore
(UTC+08:00) Kuala Lumpur, Singapore
(UTC+08:00) Kuala Lumpur, Singapore
(UTC+08:00) Kuala Lumpur, Singapore
(UTC+08:00) Kuala Lumpur, Singapore
(UTC+08:00) Kuala Lumpur, Singapore
(UTC+08:00) Kuala Lumpur, Singapore
(UTC+08:00) Kuala Lumpur, Singapore

我想放弃＆＃34; +8：00＆＃34;如果是吉隆坡，新加坡

Answer 1

如果这只是varchar列，那么这可以有效：

DECLARE @t TABLE(TimeZone NVARCHAR(max))

INSERT INTO @t VALUES
('(UTC-12:00) International Date Line West'),
('(UTC-08:00) Baja California'),
('(UTC+05:30) Chennai, Kolkata, Mumbai, New Delhi'),
('(UTC+08:00) Kuala Lumpur, Singapore')


SELECT TimeZone, SUBSTRING(timezone, 5, 6) AS Time FROM @t

输出：

TimeZone                                         Time
(UTC-12:00) International Date Line West         -12:00
(UTC-08:00) Baja California                      -08:00
(UTC+05:30) Chennai, Kolkata, Mumbai, New Delhi  +05:30
(UTC+08:00) Kuala Lumpur, Singapore              +08:00

从时区列中获取时间

1 个答案: