我在表单上有一个元素:
<img src="/media/BodyPart_7d0cf57e-a461-44fd-903f-ce77b005e299/300/0" class="media-item">
我想提取Bodypart_xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx
这里是字符串"/{anyt-ext-here}/BodyPart_xxxxxxxx-xxxx-xxxx-xxxx-xxxxxxxxxxxx/{any-number-here}/{any-number-here}"
doint最好的一天是什么?
答案 0 :(得分:1)
类似的东西:
var output= document.querySelector("#output");
var img= document.querySelector(".media-item"); //assuming there is only the wanted img of this class
var extracted_string= img.src.match(/BodyPart[^\/]*/);
if( extracted_string )
output.innerHTML= extracted_string;
else
output.innerHTML= "no match found";
&#13;
<img src="/media/BodyPart_7d0cf57e-a461-44fd-903f-ce77b005e299/300/0" class="media-item">
<div id="output"></div>
&#13;
答案 1 :(得分:1)
试试这段代码:
var input = "<img src=\"/media/BodyPart_7d0cf57e-a461-44fd-903f-ce77b005e299/300/0\" class=\"media-item\">";
var matches = input.match(/^<img src=.*\/(BodyPart\_\w{8}\-\w{4}\-\w{4}\-\w{4}\-\w{12})\//);
alert(matches[1]);
输出:
BodyPart_7d0cf57e-a461-44fd-903f-ce77b005e299
答案 2 :(得分:1)
尝试使用.split()
,.filter()
var img = document.querySelectorAll("img[src*=BodyPart]")[0];
var res = img.src.split("/").filter(function(src, i) {
return /BodyPart/.test(src)
})[0];
console.log(res);
<img src="/media/BodyPart_7d0cf57e-a461-44fd-903f-ce77b005e299/300/0" class="media-item">