Question

脚本：

$('.removeVehicle').click(function() {
    var $this = $(this),
        $row = $(this).parent().parent();

    alert($row.attr('data-vehicle-id'));

    if (confirm("Delete vehicle? ") == true) {
        $.post("removevehicle.php", {Id: $row.attr('data-vehicle-id')});
    };
});

HTML / PHP：

<?php while ($row = $products->fetch_assoc()) { ?>
    <tr data-vehicle-id="<?= $row['Vehicle_ID']?>">
        <td class="VRM"><?= $row['VRM']; ?></td>
        <td class="Make"><?= $row['Make']; ?></td>
        <td class="Model"><?= $row['Model']; ?></td>
        <td class="Colour"><?= $row['Colour']; ?></td>
        <td class="Mileage"><?= $row['Mileage']; ?></td>
        <td class="Advertised Price">£<?= $row['Advertised_Price']; ?></td>
        <td class="Date of Registration"><?= $row['Date_of_Registration']; ?></td>
        <td class="HPi Status"><?= $row['HPI_Status']; ?></td>
        <td class="actions">
            <button class="editLine">Edit line</button>
            <button class="saveLine hide">Save line</button>
            <button class="startSale" onclick="div_showSale()">Start Sale</button>
            <button class="removeVehicle"><img id="trash" src="images/trash.png" alt="Delete Vehicle" height=20 width=20></button>
        </td>
    </tr>
 <?php } ?>

removevehicle php：

<?php 
require 'config/init.php';

if (isset($_SESSION['myusername'])) {
    $mysqli = new mysqli($db['hostname'], $db['username'], $db['password'], $db['database']);

    if ($mysqli->connect_errno) {
        printf("Connect failed: %s\n", $mysqli->connect_error);
        exit();
    }
    $queryStr = "DELETE FROM VEHICLE WHERE Vehicle_ID = '" . $_POST['Id'] . "'";


    $query = $mysqli->query($queryStr);

}

使用车辆ID一直工作到警报点（警报正确的车辆ID）。基本上我需要做的就是从数据库中删除车辆/记录 - 任何更好的建议或如何使当前方法有效？

一旦我完成了这项工作，我将更改MySQLi查询以抵消注入（它尚未生效）。

Answer 1

使用.data()获取您的数据属性信息。还要返回PHP结果并将其转储到console。最后，检查控制台是否有错误。请改用：

PHP：

$query = $mysqli->query($queryStr);
echo $query;

JS：

$('.removeVehicle').click(function() {
    var $this = $(this),
        $row = $(this).parent().parent();

    var vehicle_id = $row.data("vehicle-id");

    if (confirm("Delete vehicle? ") == true) {
        $.post("removevehicle.php", {Id: vehicle_id}, function(result) {
            console.log(result);
        });
    }
});

Answer 2

我认为问题在于sql查询并将vehicle_id包装在引号中？

如果您想要在回调中删除该行，请执行以下操作：

$.post("removevehicle.php", {Id: $row.attr('data-vehicle-id')}, function() {
    // delete the row
});

用于从数据库中删除记录的按钮

2 个答案: