我正在建立一个快速的游戏并且需要建立一个班级。我的代码适用于我班级中的所有元素,但不适用于此。
func saveInformationMember(){
var MembersDefaultName = NSUserDefaults.standardUserDefaults()
MembersDefaultName.setValue(globalCurrentMembers, forKey: "globalCurrentMembersData")
MembersDefaultName.synchronize()
}
GlobalCurrentMembers
是Member
的数组,如下所示:
class Member {
var image = String ()
var name = String ()
var progression = Int()
var round = Int()
var level = Int()
var imageProgression = [UIButton]()
func Init(){
image = "default.png"
name = "default"
progression = 0
round = 0
level = 0
}
提前帮忙。
答案 0 :(得分:0)
要以这种方式保存您的课程,Member
需要符合NSCoding
协议。
答案 1 :(得分:0)
对Aaron Brager来说是回应。这是回复:
func saveInformationMember(){
let data = NSKeyedArchiver.archivedDataWithRootObject(globalCurrentMembers)
NSUserDefaults.standardUserDefaults().setObject(data, forKey: "member")}
func loadInformationMember(){
if let data = NSUserDefaults.standardUserDefaults().objectForKey("member") as? NSData {
globalCurrentMembers = NSKeyedUnarchiver.unarchiveObjectWithData(data) as [Member]
}
我的班级:
class Member : NSObject, NSCoding {
var image = String ()
var name = String ()
var progression = Int()
var round = Int()
var level = Int()
var imageProgression = [UIButton]()
func initiation(){
image = "default.png"
name = "default"
progression = 0
round = 0
level = 0
}
required convenience init(coder decoder: NSCoder) {
self.init()
self.image = decoder.decodeObjectForKey("image") as String!
self.name = decoder.decodeObjectForKey("name") as String!
self.progression = decoder.decodeIntegerForKey("progression") as Int!
self.round = decoder.decodeIntegerForKey("round") as Int!
self.level = decoder.decodeIntegerForKey("level") as Int!
}
func encodeWithCoder(coder: NSCoder) {
coder.encodeObject(self.image, forKey: "image")
coder.encodeObject(self.name, forKey: "name")
coder.encodeInt(Int32(self.progression), forKey: "progression")
coder.encodeInt(Int32(self.round), forKey: "round")
coder.encodeInt(Int32(self.level), forKey: "level")
}}