Question

我正在尝试将变量从html表单传递到.php脚本，然后从.php脚本传递到存储变量值的.txt文件中。问题是，当我测试脚本而不是发布变量号时，它只是发布变量名称＆＃34; numberVariable＆＃34;。

HTML / JavaScript的

    <form id="payment-form" action="chargeCard.php" method="POST" name="payment-form">
                            <input onkeypress="return isNumberKey(event)" type="text" name="amount" id="amount" />
                            <input type="hidden" id="numberVariable" name="numberVariable" value="numberVariable"/> <!--this is where I try to pass the variable to the .php script-->
                            <input type="image"  src="Button1.png" id="customButton" value="pay" alt="button"/>

                            </form>

    <script type="text/javascript">
                            function isNumberKey(evt)
                        {
                        var charCode = (evt.which) ? evt.which : event.keyCode
                        if (charCode > 31 && (charCode < 48 || charCode > 57))
                        return false;

                        return true;
                        }
                        </script>

<script type="text/javascript"> 

                            var numberVariable= 1; //this is the variable I am trying to pass to the .php script to then pass the value to the .txt file

                            document.getElementById("numberVariable").innerHTML = numberVariable;
                            document.getElementByID("numberVariable").value = numberVariable;

                        </script>

PHP

<?php 

    require_once('./stripe-php/init.php');

    \Stripe\Stripe::setApiKey("removed for safety");

    $token = $_POST['stripeToken'];
    $myAmount = $_POST['amount'];
    $describtion = $_POST['description'];

    $numberVariable= $_POST['numberVariable']; //this is where I get the variable from the form

    $myAmount = round((int)$myAmount*100,0);

    try {
    $charge = \Stripe\Charge::create(array(
    "amount" => $myAmount,
    "currency" => "usd",
    "source" => $token,
    "description" => $describtion));

    //PASTE VARIABLE TO .TXT FILE START

    $filename = "iPhoneAuctionBids.txt";
    $content = file_get_contents($filename);
    $content .= $numberVariable. PHP_EOL;
    file_put_contents($filename, $content);

    //PASTE VARIABLE TO .TXT FILE END

    } catch(\Stripe\Error\Card $e) {
    }

?>

Answer 1

你不对文件做任何事情。

您需要打开文件并将该值写入其中。

$filename = "iPhoneAuctionBids.txt"; 
$content = file_get_contents($filename);
$content .= $numberVariable . PHP_EOL;
file_put_contents($filename, $content);

此外，您可能希望在对DOM执行任何js处理之前等待生成html。把你的JS代码放在

中

window.onload(function(){
// here
});

Answer 2

您必须实际打开文件并将新数据写入其中。您所要做的就是使用文件名设置本地变量，而不是打开它，也不是获取内容。 http://php.net/manual/en/function.fopen.php是您首先需要阅读的内容。

将变量传递给.txt文件

HTML / JavaScript的

PHP

2 个答案: