Question

我想生成数字（随机），使得数字遵循给定均值和方差的正态分布。我怎样才能做到这一点？

如果你能在Java的上下文中给出它会更好。人们可能会在这些答案中寻求帮助：但它们并不准确。 Generate random numbers following a normal distribution in C/C++

Answer 1

无耻地用Google搜索并取自：http://www.javapractices.com/topic/TopicAction.do?Id=62

魔法＆＃39;发生在Random.nextGaussian()

内

import java.util.Random;

/** 
 Generate pseudo-random floating point values, with an 
 approximately Gaussian (normal) distribution.

 Many physical measurements have an approximately Gaussian 
 distribution; this provides a way of simulating such values. 
*/
public final class RandomGaussian {

  public static void main(String... aArgs){
    RandomGaussian gaussian = new RandomGaussian();
    double MEAN = 100.0f; 
    double VARIANCE = 5.0f;
    for (int idx = 1; idx <= 10; ++idx){
      log("Generated : " + gaussian.getGaussian(MEAN, VARIANCE));
    }
  }

  private Random fRandom = new Random();

  private double getGaussian(double aMean, double aVariance){
    return aMean + fRandom.nextGaussian() * aVariance;
  }

  private static void log(Object aMsg){
    System.out.println(String.valueOf(aMsg));
  }
}

生成遵循Java中的正态分布的数字

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