Question

代码允许我输入超过六次，而且它不会打印else语句。我的代码是：

import random
secret = random.randint(1, 99)
guess = 0
tries = 0
print ('AHOY! I am the Dread Prites Roberts , and i have a secret!')
print ('It is a number from 1 to 99. I\'ll give you 6 tries ')

while guess != secret and tries < 6:
guess = int(input('What is your guess? '))
if guess < secret:
     print ('Too Low, you scurvy dog!')
elif guess > secret:
     print ('Too high, boy')
     tries = tries + 1
elif guess == secret: 
     print ('Avast! you got it ! Found my seceret , you did!')
else:
     print ('No more guess! Better Luck next time')
     print ('The secret number was',secret)

我在Python 3.4中尝试了代码。它打印结果超过六次。虽然猜测不等于秘密并且尝试...在6次尝试之后它将打印'No more guess better luck next time'但是一次又一次地执行

Answer 1

你有一个缩进问题（我想通过粘贴发生）但你的主要问题是，当猜测太高时你只是递增tries。你也应该将最后一个if if移出while块，因为while条件已经处理了vars。

您的实施应如下所示：

import random
secret = random.randint(1, 99)
guess = 0
tries = 0
print ('AHOY! I am the Dread Prites Roberts , and i have a secret!')
print ('It is a number from 1 to 99. I\'ll give you 6 tries ')

while guess != secret and tries < 6:
    guess = int(input('What is your guess? '))
    tries = tries + 1
    if guess < secret:
         print ('Too Low, you scurvy dog!')
    elif guess > secret:
         print ('Too high, boy')

if guess == secret: 
    print ('Avast! you got it ! Found my seceret , you did!')
else:
    print ('No more guess! Better Luck next time')
    print ('The secret number was',secret)

随机密码的代码

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