Question

   <recipes>
  <recipe name="MPEG4w480f20h360AAC" mimeType="video/mp4" width="480" height="360" />
  <recipe name="MP3" mimeType="audio/mpeg" />
  <recipe name="j24" mimeType="image/jpeg" width="24" height="24" />
  <recipe name="j64" mimeType="image/jpeg" width="64" height="64" />
  <recipe name="j128" mimeType="image/jpeg" width="128" height="128" />
  <recipe name="j88" mimeType="image/jpeg" height="88" />
  <recipe name="j150" mimeType="image/jpeg" height="150" />
  <recipe name="hqPivot" mimeType="image/jpeg" width="600" />
   </recipes>

我正在编写Ruby脚本来验证XML结构。

assert(!XPath.match(xml, "recipes/recipe[@name]").empty?, "Structure of xml incorrect")

如何逐一验证所有内容？

Answer 1

使用Nokogiri：

require 'nokogiri'

f = File.open("test.xml")
doc = Nokogiri::XML(f)

tags = []

doc.xpath("//recipe/@name").each do |elem| # get all name of all recipes
  tags << elem.value
end

p tags # show all tags
p tags == tags.uniq # are all tags unique?

f.close

此输出（使用您的样本）：

["MPEG4w480f20h360AAC", "MP3", "j24", "j64", "j128", "j88", "j150", "hqPivot"]
true

如何使用ruby解析重复标记的XML？

1 个答案: