C语言错误中的词法分析器

时间:2015-04-01 09:24:06

标签: lexical-analysis

我想用C来源,但我的程序中有错误

#include<stdio.h>
#include<ctype.h>
#include<string.h>
void keyw(char *p);
int i=0,id=0,kw=0,num=0,op=0;
char keys[32][10]={"auto","break","case","char","const","continue","default",
"do","double","else","enum","extern","float","for","goto",
"if","int","long","register","return","short","signed",
"sizeof","static","struct","switch","typedef","union",
"unsigned","void","volatile","while"};
main()
{
	char ch,str[25],seps[15]=" \t\n,;(){}[]#\"<>",oper[]="!%^&*-+=~|.<>/?";
	int j;
	char fname[50];
	FILE *f1;
	//clrscr();
printf("enter file path (drive:\\fold\\filename)\n");
scanf("%s",fname);
f1 = fopen(fname,"r");
//f1 = fopen("Input","r");
	if(f1==NULL)
	{
	 printf("file not found");
	 exit(0);
	}
	while((ch=fgetc(f1))!=EOF)
	{
for(j=0;j<=14;j++)
{
if(ch==oper[j])
{
printf("%c is an operator\n",ch);
op++;
str[i]='\0';
keyw(str);
}
}
for(j=0;j<=14;j++)
{
if(i==-1)
break;
if(ch==seps[j])
{
if(ch=='#')
{
while(ch!='>')
{
printf("%c",ch);
ch=fgetc(f1);
}
printf("%c is a header file\n",ch);
i=-1;
break;
}
if(ch=='"')
{
do
{
ch=fgetc(f1);
printf("%c",ch);
}while(ch!='"');
printf("\b is an argument\n");
i=-1;
break;
}
str[i]='\0';
keyw(str);
}
}
if(i!=-1)
{
str[i]=ch;
i++;
}
else
i=0;
	}
printf("Keywords: %d\nIdentifiers: %d\nOperators: %d\nNumbers: %d\n",kw,id,op,num);
//getch();
}
void keyw(char *p)
{
int k,flag=0;
for(k=0;k<=31;k++)
{
if(strcmp(keys[k],p)==0)
{
printf("%s is a keyword\n",p);
kw++;
flag=1;
break;
}
}
if(flag==0)
{
if(isdigit(p[0]))
{
printf("%s is a number\n",p);
num++;
}
else
{
//if(p[0]!=13&&p[0]!=10)
if(p[0]!='\0')
{
printf("%s is an identifier\n",p);
id++;
}
}
}
i=-1;
}

eroor

C:\ Users \ Jurs \ Documents \ abc \ main.cpp在函数'int main()'中:

13 27 C:\ Users \ Jurs \ Documents \ abc \ main.cpp [错误]字符数组的初始化字符串太长[-fpermissive]

25 9 C:\ Users \ Jurs \ Documents \ abc \ main.cpp [错误]'exit'未在此范围内声明

28 C:\ Users \ Jurs \ Documents \ abc \ Makefile.win目标'main.o'的配方失败

1 个答案:

答案 0 :(得分:0)

尝试更改

seps[15]=" \t\n,;(){}[]#\"<>"

seps[16]=" \t\n,;(){}[]#\"<>"

也可以尝试更改

main()

int main()

也许改变

exit(0);

return 0;