Question

我有一张庞大的定价数据表，其中包含以下列

source, product, term, miles, price

数据看起来像这样

LL, PH, 3, 10000, 100.00
BA, PH, 3, 10000, 200.00
LL, CH, 3, 10000, 300.00
BA, CH, 3, 10000, 400.00

我需要创建一个查询来过滤行，以便仅显示每个唯一来源/产品/期限/里程组合的最低价格的行。因此，在上面的示例中，我希望最终得到：

LL, PH, 3, 10000, 100.00
BA, PH, 3, 10000, 200.00

任何帮助表示赞赏。感谢。

Answer 1

您可以使用ROW_NUMBER()：

SQL Fiddle

SELECT
    source, product, term, miles, price
FROM(
    SELECT *,
        RN = ROW_NUMER() OVER(PARTITION BY source, product, term, miles ORDER BY price)
    FROM [your_table]
)t
WHERE RN = 1

或根据代码的编码评论，您可以使用MIN()和GROUP BY：

SQL Fiddle

SELECT
    source, product, term, miles, price = MIN(price)
FROM [your_table]
GROUP BY source, product, term, miles

Answer 2

使用NOT EXISTS返回同一来源不存在较低价格的行：

select source, product, term, miles, price
from tablename t1
where not exists (select 1 from tablename t2
                  where t1.source = t2.source
                    and t2.price < t1.price)

如果您希望源/产品组合具有最低价格，请将产品添加到子选择条件中：

select source, product, term, miles, price
from tablename t1
where not exists (select 1 from tablename t2
                  where t1.source = t2.source
                    and t1.product = t2.product 
                    and t2.price < t1.price)

等

如果有平局，则会返回两行！

Answer 3

SELECT
    source, product, term, miles, MIN(price) AS price
FROM [table_name]
GROUP BY source, product, term, miles

SQL过滤器以获得最低价格

3 个答案: