Question

我目前正在尝试为传递到存储过程的xml变量选择多个节点。但我只从它的xml中获得一个节点。如何列出所有项目名称和字符串值？

测试代码：

DECLARE @T TABLE (AllXml ntext)

INSERT @T VALUES('<error>
        <item name="item 1">
        <value string="string 1" />
        </item>
        <item name="item 2">
        <value string="string 2" />
        </item>
        <item name="item 3">
        <value string="string 3" />
        </item>
        </error>')

SELECT 
    CAST(AllXml as xml).value('(/error/item/@name)[1]', 'varchar(100)' ),
    CAST(AllXml as xml).value('(/error/item/value/@string)[1]', 'varchar(max)' )
        FROM @T

期望的结果：

Item 1     string 1
Item 2     string 2
Item 3     string 3

Answer 1

您可以使用CROSS Apply来实现它。并Sub-Select。

SELECT 
    m.c.value('(@name)[1]', 'varchar(100)') AS Name,
    m.c.value('(value/@string)[1]', 'varchar(max)') AS Value
FROM 
     (
        SELECT CAST(AllXml as xml) AllXml 
        FROM @T
     ) AS data
    CROSS APPLY AllXml.nodes('/error/item') as m(c)

或者你可以再使用CROSS APPLY，如下所示

   SELECT 
        m.c.value('(@name)[1]', 'varchar(100)') AS Name,
        m.c.value('(value/@string)[1]', 'varchar(max)') AS Value
    FROM @T
        CROSS APPLY (SELECT CAST(AllXml AS XML)) as D(D)
        CROSS APPLY D.D.nodes('/error/item') as m(c)

使用交叉应用选择多个xml节点

1 个答案: