晚上好。
我的CSV数据如下所示。
level,label,price
1,menu1,3000
2,menu1_1,5000
2,menu1_2,6000
2,menu1_3,7000
1,menu2,8000
2,menu2_1,5000
3,menu2_1_1,5000
3,menu2_1_2,7000
2,menu2_2,6000
2,menu2_3,7000
1,menu3,9000
1,menu4,10000
我想将此数据转换为json数据,如下所示。你应该写一个递归表单来编写我看到的任何javascript代码吗?
[
{
"id": 1,
"label": "menu1",
"price": "3000",
"children": [
{
"id": 2,
"label": "menu1_1",
"price": "5000",
"children": []
},
{
"id": 3,
"label": "menu1_2",
"price": "6000",
"children": []
},
{
"id": 4,
"label": "menu1_1",
"price": "7000",
"children": []
}
]
},
{
"id": 5,
"label": "menu2",
"price": "8000",
"children": [
{
"id": 6,
"label": "menu2_1",
"price": "5000",
"children": [
{
"id": 7,
"label": "menu2_1_1",
"price": "5000",
"children": []
},
{
"id": 8,
"label": "menu2_1_2",
"price": "7000",
"children": []
}
]
},
{
"id": 9,
"label": "menu2_2",
"price": "6000",
"children": []
},
{
"id": 10,
"label": "menu2_3",
"price": "7000",
"children": []
}
]
},
{
"id": 11,
"label": "menu3",
"price": "9000",
"mnu_img": "",
"index": 46,
"children": []
},
{
"id": 12,
"label": "menu4",
"price": "10000",
"mnu_img": "",
"index": 50,
"children": []
}
]
但是,我有一个转换导入CSV源。 注意网址:http://techslides.com/convert-csv-to-json-in-javascript
感谢您的回答。但是下面显示的问题很少。
我不需要array[0]
请帮助我。
答案 0 :(得分:1)
首先我将csv数据解析为js对象:
var array = data.split("\n").map(function(row, index) {
var arr = row.split(",")
return {
id: index+1,
level: +arr[0],
label: arr[1],
price: arr[2],
children: []
}
})
然后我添加一个0级,这样所有东西都有一个父级:
array.unshift({ level: 0, children: [] })
var parents = array.slice(0,1)
我循环数据,将level参数与前一个参数进行比较。我还将父母保持在一个堆栈中,底层为0级父级。
for(var i=1; i<array.length; i++) {
var prev = array[i-1]
var obj = array[i]
var p = parents[parents.length-1]
if(obj.level > prev.level) {
parents.push(prev)
p = prev
} else if (obj.level < prev.level) {
do {
p = parents.pop()
} while(obj.level < p.level)
p = parents[parents.length-1]
}
p.children.push(obj)
}
最后我读出了结果
var result = parents[0].children
console.log(result)